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nalin [4]
3 years ago
14

Of the 13 people who show up, three are women. how many ways are there to choose 10 players to take the field if at least one of

these players must be a woman?
Mathematics
1 answer:
Nata [24]3 years ago
7 0
There are 165 ways to choose the players with at least one woman.

(1+2+3+4+5+6+7+8+9+10) x 3.

The addition is the number of combinations you can have with the men, then you multiply it by 3 because there are 3 women.
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Pls help! 50 POINTS!
nirvana33 [79]

Answer:

See below.

Step-by-step explanation:

1)

So we have the equation:

2x+3y=1470

To change into the slope-intercept form, we need to isolate the y-variable. Thus, subtract 2x from both sides:

(2x+3y)-2x=(1470)-2x

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Now, divide both sides by 3. The left side cancels:

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The slope-intercept form is:

y=mx+b

Where m is the slope and b is the y-intercept.

Thus, the slope is -2/3 and the y-intercept is 490.

2)

So, since we already know the y-intercept is 490, plot a point at (0,490).

The slope is too small to use. Thus, multiply the fraction by 100. It is now (-200/300). This means that we move <em>down</em> 200 for every 300 (recall that the slope means rise over run. Thus, we move down 200 for every 300 to the right). Thus, another possible point would be (0+300,490-200) or (300,290). Plot that. Then, connect them.

3)

To write in in function notation, simply substitute the y-variable for the function notation. Our independent variable here is x so we'll use that.

y=-\frac{2}{3}x+490\\ f(x)=-\frac{2}{3}x+490

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For example, if 105 sandwiches were made, then f(105)=-2/3(105)+490=420 wraps were made for the total profit to be $1,470.

4)

Please refer to the attached graph.

5)

First, since the total profit has now increased, the graph above and to the right of the old graph. This is because Sal needs to sell more sandwiches and wraps. Likewise, because of this, the x- and y-intercepts will also be different. Nevertheless, if converted into the slope-intercept equation, the slope will remain the same.

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