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Sergio [31]
3 years ago
11

Please, help. Find the value of the expression.

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0
I hope this helps step by step

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A chair for an adult is 20 in. tall and 16 in. wide. A builder
Mashcka [7]

Answer:

4 in. wide

Step-by-step explanation:

20/5=4

4x=16

4x/4=16/4

x=4

3 0
3 years ago
Plz help me what is the answers
Lyrx [107]

4x + 1(2x - 3)

4x + 2x - 3

6x - 3

- 18

4 0
3 years ago
A box is to be made from a rectangular piece of corrugated​ cardboard, where the length is 8 more inches than the​ width, by cut
Ksenya-84 [330]
The volume of a box like this is found by multiplying the length times the width times the height.  We are told that the length is 8 more inches than the width, so the width is w and the length is w + 8.  If we cut away 3 square inches from each corner, the height when we fold up those corners is going to be 3.  The volume is given as 27, so our formula looks like this:  27=(3)(w)(w+8).  When we do that multiplication, we have  27=3w^2+24w.  We need to solve for w so we can then solve for h.  Move the 27 over and set the quadratic equal to 0.  3w^2+24w-27=0.  We can then factor out a 3 to make the job easier:  3(w^2+8w-9)=0.  Now we can factor to solve for w.  The 2 numbers that add up to 8 and multiply to -9 are 9 and -1.  So (w+9) = 0, (w-1) = 0, or 3 = 0.  Of course 3 doesn't equal 0, so that's out.  w + 9 = 0 so w = -9.  w - 1 = 0 so w = 1.  There are 2 things in math that can never EVER be negative and those are time and distance/length.  So -9 is out.  That means that w = 1.  But don't forget that there was 6 inches cut off each side, so the width is 1 + 3 + 3 which is 7.  The length is w + 8 which means that the length is 7 + 8 or 15.  Those are the dimensions of the rectangle before it was cut.
4 0
4 years ago
1. z²-9z=66<br> 2. y²+16y=17<br> 3. 2h²-5h=-1
soldier1979 [14.2K]

Hello,

Starting with problem one:

Subtract 66 from both sides.

z2−9z−66=66−66

z2−9z−66=0

Use quadratic formula with a=1, b=-9, c=-66.

z = 9/2+1/2√345

Problem two:

Subtract 17 from both sides.

y^2+16y−17=17−17

y^2+16y−17=0

Factor left side of equation.

(y−1)(y+17)=0

Set factors equal to 0.

y−1=0 or y+17=0

y=1 or y=−17

ANSWER: y=1 or y=−17

Problem 3:

2h^2−5h−(−1)=−1−(−1)

2h^2−5h+1=0

Use quadratic formula with a=2, b=-5, c=1.

ANSWER: h=5/4+1/4√17

Have an amazing day.

7 0
3 years ago
Can someone please help me out with this
natima [27]

Answer:

-1 will be the answer.

hope this is helpful. ^_^

6 0
3 years ago
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