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3 years ago

Match each expression with an equivalent expression.

Mathematics

2 answers:

Svetach [21]3 years ago

6 0

Answer:

6x-4y=2(3x-2y),

6-4x=2(3-2x),

6x-4x=2x,

6x-4=2(3x-2)

Step-by-step explanation:

We have been given 4 expressions

6x−4y, 6−4x, 6x−4x, 6x−4

Now we need to simplify or factor so that we can match each expression with an equivalent expression.

6x-4y=2(3x-2y)

6-4x=2(3-2x)

6x-4x=2x

6x-4=2(3x-2)

Now we can easily see that right side is unique for each of the given expression which can be easily matched with given choices.

Marysya12 [62]3 years ago

3 0

Answer:

$6x-4y$ → 4. $2(3x-2y)$

$6-4x$ → 3. $2(3-2x)$

$6x-4x$ → 1. $2x$

$6x-4$ → 2. $2(3x-2)$

Step-by-step explanation:

You need to:

Factor out 2 from $6x-4y$ , then you get the equivalent expression:

$=2(3x-2y)$ this matches with OPTION 4

Factor out 2 from $6-4y$ , then you get the equivalent expression:

$=2(3-2x)$ this matches with OPTION 3

Make the subtraction for $6x-4x$ , then you get the equivalent expression:

$=2x$ this matches with OPTION 1

Factor out 2 from $6x-4$ , then you get the equivalent expression:

$=2(3x-2)$ this matches with OPTION 2

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When fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz t

sweet-ann [11.9K]

Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = $\frac{2}{3}s$
distance the train travel = $\frac{1}{2}(s+15)$

The question: Assume that the train travels the same distance as the car
==> $\frac{2}{3}s = \frac{1}{2}(s+15)$
==> $\frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}$
==> $\frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}$
==> $\frac{1}{6}s = \frac{15}{2}$
==> $\frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}$
==> $s = 45$
Now we know that Fritz drive at 45 mph,
distance = $\frac{2}{3} * 45 = 30 miles$