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Scorpion4ik [409]
4 years ago
14

Write an integer to describe each situation. a town sits 380 feet below sea level

Mathematics
1 answer:
oee [108]4 years ago
6 0

-380, because it is below the sea level

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Starting at 6 a.m. every morning, Matilda receives text messages on her cell phone from her mother, her best friend, and her bro
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Answer:

a) 0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

b) 1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A) Find the probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

Two from the best friend:

Her best friend sends a message once every 10 minutes.

From 6 to 7:30, there is an hour and a half, that is, 90 minutes, so the mean for her best friend is \mu = \frac{90}{10} = 9

Two messages is P(X = 2). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-9}*9^{2}}{(2)!} = 0.0050

Two from the mother:

Message every hour = 60 minutes. So \mu = \frac{90}{60} = 1.5. This is P(X = 2).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-1.5}*1.5^{2}}{(2)!} = 0.2510

Two of her best friend and two of her mother:

Independent events, so the probability of both happening is the multiplication of their separate probabilities.

p = 0.005*0.251 = 0.0013

0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

B) With a chance of 75% a text message contains a typo independent of the sender. Find the probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

In 3 hours, she is expected to receive:

3*60/10 = 18 messages from her best friend.

3*60/60 = 3 messages from her mother.

3*60/30 = 6 messages from her brother.

In total, 27 messages.

75% probability of a typo, so \mu = 0.75*27 = 20.25

This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20.25}*20.25^{0}}{(0)!} = 1.6 \times 10^{-9}

1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

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Answer:

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By identifying that it is a translation of the natural logarithm, we see that the function is:

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We can see that the function has a logarithmic behavior. We know that the function:

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For our function, we can see that the asymptote is at x = 5 and the zero is at x = 6. So the graphed function seems to be the natural logarithm translated 5 units to the right.

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