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SSSSS [86.1K]
3 years ago
11

A 9 cm tall cone shaped paper cup can hold up to 58.9 cm cubed of water. What is the minimum amount of paper needed to make the

paper cup, assuming no overlap in the paper? Use 3.14 for π.
Mathematics
1 answer:
babymother [125]3 years ago
4 0
Volume of a cone, V = πr^2h/3

r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum

Surface area, A = πr [r+ Sqrt (h^2+r^2)] =  3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2

Therefore, minimum amount of paper required is 92.95 cm^2
You might be interested in
Count by tens and ones to find the sum of 45+26
galben [10]
45+10= 55
55+10= 65
65+1= 66
66+1= 67
67+1= 68
68+1= 69
69+1= 70
70+1= 71

Because 10+10+1+1+1+1+1+1= 26,
71 is your answer :)
4 0
3 years ago
Find the surface area of the cylinder formed by the net. Use 3.14 for π.
sineoko [7]

Answer:

138.16 square feet

Step-by-step explanation:

The surface area of the cylinder consists of one rectangle and two circles.

1. The radius of the circle is 4 ft, then the area of the circle is

A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2

2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.

Find the circumference:

C=2\pi r=2\pi \cdot 4=8\pi \ ft

Hence,

A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2

3. The surface area of the cylinder is

SA=2A_{circle}+A_{rectangle}=\\ \\=2\cdot 16\pi +12\pi =32\pi +12\pi =44\pi \approx \\ \\\approx 44\cdot 3.14=138.16\ ft^2

8 0
3 years ago
Can anyone plz help me with this problem im a little stuck on it...
Greeley [361]

Answer:

18

Step-by-step explanation:

3×6 = 18

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ÷)

6 0
3 years ago
Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
1 year ago
What is the surface area in square meters of a cylinder with a radius of 3.4 meters and a height of 2.8 meters. Please show work
ohaa [14]
132.45 m^2..........
5 0
3 years ago
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