All categories

3 years ago

PLS HELP ASAP PLS GIVE A GOOD EXPLANATION

Mathematics

2 answers:

taurus [48]3 years ago

4 0

Negative integer.

-761 + 317= -444

Plug the answer in:

-761 - (-444)
= -317

Reminder: when multiplying two negatives, you get a positive.

Anna71 [15]3 years ago

4 0

Answer:

-444

Step-by-step explanation:

-761 - (-317) = ?

? = -444

Also, Why do you have hw on the weekend fran?

You might be interested in

0.38x < 25 -10.81 - 10

marusya05 [52]

Answer:

Inequality Form :

x < 11.02631578

Interval Notation :

( − ∞, 11.02631578)

4 0

3 years ago

Read 2 more answers

Describe the relationship between n and 4 that will make the value of the expression 7xn4greater than7

valina [46]

Answer:

As per the statement: the value of the expression 7 x n/4 greater than 7.

To describe the relationship between n and 4.

"greater than" symbol is represented by '>'

The value of expression $7 \times \frac{n}{4}$ grater than 7 is;

$7(\frac{n}{4}) > 7$

Divide by 7 both sides we get;

$\frac{n}{4} > 1$

Multiply both sides of an equation by 4 we get;

$n > 4$

Therefore, the relationship between n and 4 is, $n > 4$

8 0

3 years ago

Each salt shaker holds 1 1/4 ounces. If a box of salt contains 10 ounces, how many shakers will it fit

Alekssandra [29.7K]

8 shakers will fit becuase 4 shakers equal 5 ounces and you multiply it by two and you get 10

3 0

3 years ago

Read 2 more answers

The carpet erin has chosen costs $2.50 per square foot . how much will it coast her to carpet the

baherus [9]

All you do is 2.5 times the number of feet so 2.5x , x is the number of feet

3 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago