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Professor Jennings claims that only 35% of the students at Flora College work while attending school. Dean Renata thinks that th

lisov135 [29]

Answer:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

Step-by-step explanation:

Information given

n=78 represent the random sample taken

X=36 represent the students with jobs

$\hat p=\frac{36}{78}=0.462$ estimated proportion of students with jobs

$p_o=0.35$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:

Null hypothesis: $p \leq 0.35$

Alternative hypothesis: $p > 0.35$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

5 0

4 years ago

the average daily maximum temperature is 21.85 Celsius and the average daily minimum temperature is -4.7 Celsius the average dai

WITCHER [35]

Hello.

To find the answer you will have to add them then divide by 2.

So if you add 21.85+-4.7 you will get the answer of 17.15.

Then divide by two to get 8.575

The answer is: 8.575 Celsius

Have a nice day

8 0

3 years ago

How do you prove that AM=1/2AB if what is given is M is the midpoint of line AB? 7 steps.

mestny [16]

because a midpoint mean middle so A----------M----------B

AM is 1/2 of AB as well as BM is 1/2 of AB

4------------5----------6 if 5 is the midpoint how much is between 4 and 5 and 5 and 6

6 0

4 years ago

Please answer as fast as possible see image

Solnce55 [7]

Answer:

388

Step-by-step explanation:

We need to find the area of the semicircle and parallelogram separately and then combine.

The formula for the area of a semicircle is 1/2(pi*r^2)

r = 12. 12^2 = 144

1/2(pi*144) = 226..1946711 which we can just round to 226

The formula for the area of a parallelogram is bh

b = 18, h = 9. 18*9 = 162.

226+162 = 388

7 0

3 years ago

Read 2 more answers

For non-zero denominators, simplify: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3a%5E3-75a%7D%7Ba%28a%2B5%29%28a%2B5%29%7D" id=

Debora [2.8K]

$\frac{3a^3-75a}{a(a+5)(a+5)}=\frac{3a(a^2-25) }{a(a+5)(a+5)}=\frac{3a(a - 5)(a+5) }{a(a+5)(a+5)} =\frac{3 (a - 5) }{ (a+5) }$

8 0

3 years ago