Answer:
839
Step-by-step explanation:
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
Answer:
A
Step-by-step explanation:
Note that for (3, 2) → (5, 3)
The x- coordinate of the image is 2 more (+ 2) than the original and the y- coordinate of the image is 1 more (+ 1) than the original, that is
(x, y ) → (x + 2, y + 1 ) ← rule to obtain image, hence
(2, 4 ) → (2 + 2, 4 + 1 ) → (4, 5 ) → A
The answer was "Probability-based inference", you got apex too?
Answer:
a(10) = 3^9 = 19683
Step-by-step explanation:
In this sequence each new term is equal to 3 times the previous term. Thus, 3 is the common ratio. The first term is 1.
The general formula for the nth term of a geometric sequence i
a(n) = a(1)*r^(n -1), where r is the common ratio.
Here, a(n) = 1*3^(n - 1), and so
the 10th term is
a(10) = 1*3^(10 - 1), or
a(10) = 3^9 = 19683