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Alex17521 [72]
3 years ago
7

What is the solution to this equation? -13x=78

Mathematics
2 answers:
lions [1.4K]3 years ago
7 0

Answer:

b. x=-6

-13x=78

x=78/-13=-6

julia-pushkina [17]3 years ago
4 0

Answer:

X=-6

Step-by-step explanation:

It is this answer because you divide each term by -13 and the you are left with -6 so X=-6

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Find the difference (20m+3)-(7m-5)
xz_007 [3.2K]

Answer:

Simplifying

(20m + 3) + -1(7m + -5) = 0

Reorder the terms:

(3 + 20m) + -1(7m + -5) = 0

Remove parenthesis around (3 + 20m)

3 + 20m + -1(7m + -5) = 0

Reorder the terms:

3 + 20m + -1(-5 + 7m) = 0

3 + 20m + (-5 * -1 + 7m * -1) = 0

3 + 20m + (5 + -7m) = 0

Reorder the terms:

3 + 5 + 20m + -7m = 0

Combine like terms: 3 + 5 = 8

8 + 20m + -7m = 0

Combine like terms: 20m + -7m = 13m

8 + 13m = 0

Solving

8 + 13m = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 13m = 0 + -8

Combine like terms: 8 + -8 = 0

0 + 13m = 0 + -8

13m = 0 + -8

Combine like terms: 0 + -8 = -8

13m = -8

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m = -0.6153846154Step-by-step explanation:

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3 years ago
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A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
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Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

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  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
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Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
4 years ago
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