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Elina [12.6K]
3 years ago
13

X/x+2 = 4/5. Solve for x.

Mathematics
2 answers:
9966 [12]3 years ago
6 0
Hey!

First, let's write the problem.
\frac{x}{x}+2=\frac{4}{5}
Since the least common multiple is 5x, we are going to multiply by that.
\frac{x}{x}\cdot \:5x+2\cdot \:5x=\frac{4}{5}\cdot \:5x
5x+10x=4x
15x=4x
Subtract 4x from both sides.
15x-4x=4x-4x
11x=0
Divide both sides by 11.
\frac{11x}{11}=\frac{0}{11}

Our final answer would be,
x=0

This tells us that this problem has no solution.

_________

Your problem may have been written like this, 
\frac{x}{\left(x+2\right)}=\frac{4}{5}
If so, there's a totally different solution, which is why important to include parenthesis. Let's simplify it.
Cross multiply. It would look something like this,
x\cdot \:5=\left(x+2\right)\cdot \:4
Apply the distributive property.
x\cdot \:5=4x+8
Subtract 4x from both sides.
x\cdot \:5-4x=4x+8-4x
This tells us that our final answer would be,
x=8

Thanks!
-TetraFish
gregori [183]3 years ago
4 0
<span>X/x+2 = 4/5

5x = 4x + 8

5x - 4x = 8

x= 8


</span>
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Step-by-step explanation:

Given data

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x1= 2

y1= 3

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substitute into the distance between two points formula

d=√((x_2-x_1)²+(y_2-y_1)²)

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2 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
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