<span>First note that y cannot equal -7 or -1 as division by zero is undefined. So that if it comes up in our solution we know that it is not a real solution.
[(y+4)/(y+7)]+1=(y+3)/(y+1) make the left side have a common denominator
(y+4+y+7)/(y+7)=(y+3)/(y+1) combine like terms on left side
(2y+11)/(y+7)=(y+3)/(y+1) cross multiply
(2y+11)(y+1)=(y+3)(y+7) expand
2y^2+13y+11=y^2+10y+21 subtract y^2 from both sides
y^2+13y+11=10y+21 subtract 10y from both sides
y^2+3y+11=21 subtract 21 from both sides
y^2+3y-10=0 expand so factoring is easier
y^2-2y+5y-10=0 factor
y(y-2)+5(y-2)=0 which is equal to
(y+5)(y-2)=0
y=-5 or 2</span>
Three and one tenths. 3+1/10
<span> (3•19x5)
Simplify ————————
19x2
</span>Dividing exponential expressions :
<span> 3.1 </span> <span> x5</span> divided by <span>x2 = x(5 - 2) = x3</span>
Canceling Out :
<span> 3.2 </span> Canceling out <span>19 </span> as it appears on both sides of the fraction line
Final result :<span> 3x<span>3</span></span>
Step 1) Solve the second equation for
x
:
x
+
3
y
=
−
5
x
+
3
y
−
3
y
=
−
5
−
3
y
x
+
0
=
−
5
−
3
y
x
=
−
5
−
3
y
Step 2) Substitute
−
5
−
3
y
for
x
in the first equation and solve for
y
:
3
(
−
5
−
3
y
)
−
2
y
=
7
−
15
−
9
y
−
2
y
=
7
−
15
−
11
y
=
7
15
−
15
−
11
y
=
15
+
7
0
−
11
y
=
22
−
11
y
=
22
−
11
y
−
11
=
22
−
11
−
11
y
−
11
=
−
2
y
=
−
2
Step 3) Substitute
−
2
for
y
in the solution to the second equation at the end of Step 1 and calculate x:
x=−5−(3×−2)
x=−5−(−6)
x=−5+6
x=1
The solution is x=1 and y=−2
