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Tatiana [17]
3 years ago
14

The formula for the volume V of a rectangular prism is V = ℓwh, where ℓ represents the length, w represents the width, and h rep

resents the height. Rearrange the quantities in this formula to give a new formula for the width of the rectangular prism.
Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer: w=\dfrac{V}{lh}

Step-by-step explanation:

Given: The formula for the volume V of a rectangular prism is V = ℓwh, where ℓ represents the length, w represents the width, and h represents the height.

We rearrange this formula by dividing  ℓh both sides of the formula to get the new formula for the width of the rectangular prism, we get'

w=\dfrac{V}{lh}

Hence, the new formula for the width of the rectangular prism. :

w=\dfrac{V}{lh}

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Hfuuf help me plsssss​
denpristay [2]

Answer:

a) 26

b) 26/3

Step-by-step explanation:

a)

1) First, you have to turn 4 1/3 into an improper fraction, so you get 13/3

2) Then you do 13/3 *6/1 =78/3 (so you multiply both numerators and denominators)

3) Lastly, 78/3 can be simplified as 26

b)

1) First you turn both fractions into improper fractions, so you get 13/5 and 10/3

2) Then you do 13/5*10/3 (so you multiply both numerators and denominators)

3) You get 130/15, which can be simplified as 26/3

4 0
3 years ago
Hi, I am new to this website :) I'm currently taking an online trig class on De Moivre's theorem and I don't understand it at al
Vladimir [108]
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.

For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes

[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))] 

it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.

For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)

[2^6(cos(40*6))+isin(40*6)],

[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)

And the answer is -32 -32 √3 i

Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i

7 0
3 years ago
32) (a)-(c) pre calculus
Harrizon [31]
Well, remember we can't take the square root of a negative

so we see that we have \sqrt{1-x^2}
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain


b. for a TI-84, go to y-editor then input 4x \sqrt{1-x^2} for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7



A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7


8 0
3 years ago
Given f(x)=4x^2-9 and g(x)=2x+3 find each function or value<br> (f-g)(4)
yulyashka [42]
(f-g)(x) = 4x²-2x-12 which,evaluated at x=4, gives 64-8-12=44
4 0
3 years ago
Solve for
lakkis [162]

Answer:

x

=

13

+

6

=

19

Step-by-step explanation:

this is so simple

4 0
2 years ago
Read 2 more answers
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