How can you break up 224 divided by 7 using distributive property

Please help with this graph

Lina20 [59]

The answer is true because it comes at an angle which is adjacent to what needs to be the answer
Hoped this helped

7 0

3 years ago

What are the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1) ?

Shtirlitz [24]

Hello Missjay12,

Step 1 :
From the coordinates we have to find the slopes and midpoints of the lines.

Step 2 :
Find the slope of the bisectors and now find the equations of two lines by using slope and one mid points.

Step 3 :
Solve any two pair of equations and find the intersection point.

Step 4 :
The point thus found is the circumcenter of the given triangle.

so the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1) is, -4, 0.

8 0

3 years ago

Read 2 more answers

Explain how the inverse and the contopositivve of a conditional are alike and how they are different

anygoal [31]

Answer:

See explanation!

Step-by-step explanation:

The contrapositive of a conditional is similar to, yet different from, the inverse of the conditional.

The best way to explain this is to create an example. You should start by creating a conditional; you can then form the conditional's inverse and contrapositive.

Here is an example:

Conditional: If C, then D. (starting statement)

Inverse: If not C, then not D. (opposite of the conditional)

Contrapositive: If not D, then not C. (reversed opposite of the conditional)

Based on the information from the example, you can conclude:

Primary Similarity:

Both the contrapositive and the inverse are opposites of the conditional (both contain not, implying something would not happen under the given circumstances, rather than something would happen under those circumstances).

Primary Difference:

The contrapositive is a reversed version of the inverse; this causes them to most commonly have different meanings.

I am sure you could find more similarities/differences, but these were the two that stood out to me the most!

I hope this helps! :)

5 0

2 years ago

Chelsea spent half of her weekly

Anvisha [2.4K]

Answer:

I believe it would be 16

Step-by-step explanation:

8 is half of 16 and if she had 8 dollars after spending half her allowance, she would've had 16 as her allowance

Final answer: Her allowance would be 16 dollars

3 0

2 years ago

Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

rusak2 [61]

Answer:

(a) The probability that the thickness is less than 3.0 mm is 0.119.

(b) The probability that the thickness is more than 7.0 mm is 0.119.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is 0.762.

Step-by-step explanation:

We are given that thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm.

Let X = thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village.

So, X ~ Normal( $\mu=5.0,\sigma^{2} =1.7^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean thickness = 5.0 mm

$\sigma$ = standard deviation = 1.7 mm

(a) The probability that the thickness is less than 3.0 mm is given by = P(X < 3.0 mm)

P(X < 3.0 mm) = P( $\frac{X-\mu}{\sigma}$ < $\frac{3.0-5.0}{1.7}$ ) = P(Z < -1.18) = 1 - P(Z $\leq$ 1.18)

= 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(b) The probability that the thickness is more than 7.0 mm is given by = P(X > 7.0 mm)

P(X > 7.0 mm) = P( $\frac{X-\mu}{\sigma}$ > $\frac{7.0-5.0}{1.7}$ ) = P(Z > 1.18) = 1 - P(Z $\leq$ 1.18)

= 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is given by = P(3.0 mm < X < 7.0 mm) = P(X < 7.0 mm) - P(X $\leq$ 3.0 mm)

P(X < 7.0 mm) = P( $\frac{X-\mu}{\sigma}$ < $\frac{7.0-5.0}{1.7}$ ) = P(Z < 1.18) = 0.881

P(X $\leq$ 3.0 mm) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{3.0-5.0}{1.7}$ ) = P(Z $\leq$ -1.18) = 1 - P(Z < 1.18)

= 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

Therefore, P(3.0 mm < X < 7.0 mm) = 0.881 - 0.119 = 0.762.

4 0

3 years ago