Im pretty sure it’s A because a squares area is base x height which would be 13x13= 169 then add the area of the triangle which would be 53.3, so 169+53.3 = 222.3
Answer:
3.5 m
Step-by-step explanation:
Use sine.
1. Set up the equation using sin = opposite / hypotenuse
sin 59 = 3/x
2. Solve
x = 3.5
A^2 - b^2 ...difference of squares
so
9m^4 - 49n^6 = (3n^2)^2 - (7n^3)^2
answer
C. 9m^4 - 49n^6
Answer:
x = 70°
Step-by-step explanation:
Clockwise from top, call the three tangent points A, B, and C. Central angle AXC is the supplement of the marked external angle, so is 140°. Arc AB is bisected by the upper ray of angle x; and arc BC is bisected by the lower ray of angle x. That is to say x is half the measure of arc AC, so is 70°.
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Attached is the output of a geometry program. The angle at lower left is 40° as in the given figure. The central angle α (70°) remains the same as tangent point C is moved around, which is to say that the measure of the angle α does not depend on the dimensions of the triangle containing α. It just depends on the fact that the triangle is tangent to the circle.