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larisa [96]
3 years ago
9

Helpppppppppp please

Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer:

-2, 4, 6, 8

6, 4, 2 ,0

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<em>Refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>attachment</em>

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7nadin3 [17]

Answer: <em>3.88 to 219</em>

               

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3 years ago
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LenKa [72]

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find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3
snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

<em><u>Solution:</u></em>

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8

On comparing the above equation with eqn 1,

m = \frac{-4}{5}

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute m = \frac{5}{4} and (x, y) = (-10, -3) in eqn 1

-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}

Substitute c = \frac{19}{2} and m = \frac{5}{4} in eqn 1

y = \frac{5}{4}x + \frac{19}{2}

The standard form of an equation is Ax + By = C

Therefore,

\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38

Thus the equation of line in standard form is found

4 0
3 years ago
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