3 years ago

Helpppppppppp please

Mathematics

1 answer:

uysha [10]3 years ago

6 0

Answer:

-2, 4, 6, 8

6, 4, 2 ,0

You might be interested in

1. Choose the correct number to continue the pattern. 0, 5, 2, 7, 4, 9, 6,

Ilya [14]

Answer:

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

How do you write 2.08 × 10^3 in standard form?

larisa [96]

Answer:

2,080

Step-by-step explanation:

5 0

3 years ago

Mrs. Powell is making a pinata for her sons birthday party. the pinata is shaped like the figure below. She wants to fill it wit

QveST [7]

Answer:

1440

Step-by-step explanation:

first you add 12 and 8 to get 20 then using the formula lwh = v you multiply 20 by 12 by 6 to get 1,440

Also can you give brainliest to all of your questions bc it really hard to get brainliest and it be really nice you can choose who i dont really care but just please do it it helps a lot

8 0

3 years ago

Given: ABCE is a rectangle. D is the midpoint of segment C E.

Daniel [21]

Answer:

b is 4 e is 5 a is 6

Step-by-step explanation:

Im biggest brain

6 0

3 years ago

What is the equation of the ellipse with foci at (5, 0), (-5, 0) and vertices (9, 0), (-9, 0)?

forsale [732]

Answer: $\dfrac{x^2}{81}+\dfrac{y^2}{56}=1$

Step-by-step explanation:

General equation of ellipse : $\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}$

Given: Vertices of ellipse : (± 9,0)

Since the vertices are of the form (± a, 0).

i.e. a=9

Thus, the major axis is along x-axis.

Also, foci of the ellipse = (±5,0)

Since, foci is of the form (± c,0), i.e. c=5

Since

$c^2=a^2-b^2\\\\\Rightarrow\ 5^2= 9^2-b^2\\\\\Rightarrow\ b^2=81-25\\\\\Rightarrow\ b^2=56$

Equation of ellipse :

$\dfrac{x^2}{9^2}+\dfrac{y^2}{56}=1\\\\\Rightarrow\ \dfrac{x^2}{81}+\dfrac{y^2}{56}=1$

Hence, the required equation : $\dfrac{x^2}{81}+\dfrac{y^2}{56}=1$

8 0

4 years ago