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2 years ago

I need help with this.

Mathematics

1 answer:

Sedaia [141]2 years ago

8 0

The two lines are parallel, no matter how long they travel they will not cross.

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It snowed from 9:43 PM to 11:37 PM. How long was it snowing?

dolphi86 [110]

Answer:

1 hour and 54 minutes and ignore this stuff sjsjsbdbsj

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2 years ago

Read 2 more answers

The differencee of 3 times a number and 18 is 39

Bingel [31]

Answer:

3x-18 = 39

3x = 57

x = 19

(3*(19))-18 = 39

57-18 = 39

3x-x+2=4

Step-by-step explanation:

hope it help

7 0

3 years ago

Jack works as a waiter and is keeping track of the tips he earns daily. about how much does jack have to earn in tips on sunday

OLga [1]

A mean is an arithmetic average of a set of observations. The amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

A mean is an arithmetic average of a set of observations. it is given by the formula,

$\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}$

As it is given that Jack makes $12 on Monday, $14 on Tuesday, $18 on Wednesday, $16 on Thursday, $26 on Friday and $22 on Saturday. And we need to know how much he should earn on Sunday, so the average is $19. Therefore, we can write,

$\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}$

$19 = \dfrac{12+14+18+16+26+22+x}{7}\\\\133 = 108 + x\\\\133-108=x\\\\x = 25$

Hence, the amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

Learn more about Mean:

brainly.com/question/16967035

5 0

2 years ago

What is the interquartile range for the data set??

kramer

Answer:

Step-by-step explanation:

First, order the numbers in order. Then find the "middle numbers" and omit them after you have divided the number set into two equals parts. Then find the median of those number sets and then subtract.

You should get 71-6 at the end which is 65.

8 0

3 years ago

Consider the initial value problem yâ€²+2y=4t,y(0)=8.

Xelga [282]

Answer:

Please read the complete procedure below:

Step-by-step explanation:

You have the following initial value problem:

$y'+2y=4t\\\\y(0)=8$

a) The algebraic equation obtain by using the Laplace transform is:

$L[y']+2L[y]=4L[t]\\\\L[y']=sY(s)-y(0)\ \ \ \ (1)\\\\L[t]=\frac{1}{s^2}\ \ \ \ \ (2)\\\\$

next, you replace (1) and (2):

$sY(s)-y(0)+2Y(s)=\frac{4}{s^2}\\\\sY(s)+2Y(s)-8=\frac{4}{s^2}$ (this is the algebraic equation)

$sY(s)+2Y(s)-8=\frac{4}{s^2}\\\\Y(s)[s+2]=\frac{4}{s^2}+8\\\\Y(s)=\frac{4+8s^2}{s^2(s+2)}$ (this is the solution for Y(s))

$y(t)=L^{-1}Y(s)=L^{-1}[\frac{4}{s^2(s+2)}+\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+L^{-1}[\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}$

To find the inverse Laplace transform of the first term you use partial fractions:

$\frac{4}{s^2(s+2)}=\frac{-s+2}{s^2}+\frac{1}{s+2}\\\\=(\frac{-1}{s}+\frac{2}{s^2})+\frac{1}{s+2}$

Thus, you have:

$y(t)=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}\\\\y(t)=L^{-1}[\frac{-1}{s}+\frac{2}{s^2}]+L^{-1}[\frac{1}{s+2}]+8e^{-2t}\\\\y(t)=-1+2t+e^{-2t}+8e^{-2t}=-1+2t+9e^{-2t}$

(this is the solution to the differential equation)

5 0

2 years ago