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jok3333 [9.3K]
3 years ago
13

I need help with this.

Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

The two lines are parallel, no matter how long they travel they will not cross.

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I need help on all of these plz
shusha [124]
Can't read the top questions mate !
8 0
3 years ago
* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both
Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective n^{th} terms as following:

Sequence A. 3n - 2

Sequence B. 10 - 2n

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the n^{th} terms of the respective sequences as equal and let us verify that.

3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}

When we talk about n^{th} terms, n here is a whole number not a fractional number.

But as per the statement as stated by Sally n is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0
2 years ago
Which number line shows the solution set for |y-9| <12
RUDIKE [14]

Answer:

Option c

y\geq-3 or y \leq 21

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function f(x) = |x|  x> 0 for all real numbers.

Then the inequation:

|y-9| \leq 12 has two cases

(y-9)    if y \geq 9  (i)

-(y-9)    if y < 9 (ii)

We solve the case (i)

y \leq 9 + 12\\y\leq21

We solve the case (ii)

-y +9 \leq 12\\-y \leq 12-9\\y \geq -3

Then the solution is:

y\geq-3 or y \leq 21

8 0
3 years ago
What true bearing is WSW equivalent to?
RSB [31]

Answer:

S 67.50° W

Step-by-step explanation:

3 0
3 years ago
Find two numbers a and b such that a+b=0 and ab=36
PolarNik [594]

Answer:

b = 6i   then a = -6i

b = -6i   then a = 6i

Step-by-step explanation:

a+b=0

ab=36

a = -b

a(b) = 36

-b * b = 36

- b^2 = 36

b^2 = -36

Take the square root of each side

sqrt(b^2) = sqrt(-36)

b =± 6i

a = - (± 6i)

so b = 6i   then a = -6i

b = -6i   then a = 6i

4 0
3 years ago
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