Question

Find the first 4 terms of the sequence.t(n) = -3n- 1b. t(15)=

Answer 1

Answer:

(a)-4, -7, -10 and -13.

(b) -46

Explanation:

Given the sequence:

$t\mleft(n\mright)=-3n-1$

(a) The first four terms are obtained by substituting n=1,2,3 and 4 respectively.

$\begin{gathered} t\mleft(1\mright)=-3(1)-1=-3-1=-4 \\ t(2)=-3(2)-1=-6-1=-7 \\ t(3)=-3(3)-1=-9-1=-10 \\ t(4)=-3(4)-1=-12-1=-13 \end{gathered}$

The first 4 terms of the sequence are -4, -7, -10 and -13.

(b)t(15)

$\begin{gathered} t(15)=-3(15)-1 \\ =-45-1 \\ =-46 \end{gathered}$