Given that AC= 1 and BC=2 what is AB?
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Let the numbers be 1k, 2k , and 3k respectively
Since the sum of their cubes is 4500,
(1k)³+(2k)³+(3k)³=4500
--> k³(36)= 4500
--> k = 5
Hence, the numbers are: 5,10 and 15 respectively
Since the sum of their cubes is 4500,
(1k)³+(2k)³+(3k)³=4500
--> k³(36)= 4500
--> k = 5
Hence, the numbers are: 5,10 and 15 respectively