Hello,
y=2
Answer C
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Answer:
P(1) = 1 - 8/27 = 19/27
The probability that at least one of them will be elected is 19/27
Step-by-step explanation:
the probability that at least one of them will be elected = 1 - probability that none of them will be elected.
P(1) = 1 - P(None) .....1
Let P(A), P(B) and P(C) represent the probability for each of the three candidates to be elected .
P(A) = P(B) = P(C) = 1/3
The probability for each of the three candidates not to be elected is
P(A)' = P(B)' = P(C)' = 1 - 1/3 = 2/3
P(None) = P(A)' × P(B)' × P(C)'= 2/3 × 2/3 × 2/3 = 8/27
From equation 1. Substituting the value of P(None)
P(1) = 1 - 8/27 = 19/27
The probability that at least one of them will be elected is 19/27
<h3>Given</h3>
regular paper costs $3.79 per ream
recycled paper costs $5.49 per ream
$582.44 was spent for 116 reams
<h3>Find</h3>
the numbers of reams of each type that were purchased
<h3>Solution</h3>
Let r and g represent the numbers of reams of regular and recycled ("green") paper, respectively.
... r + g = 116 . . . . . . . . 116 reams were purchased
... 3.79r + 5.49g = 582.44 . . . . this is the total cost of the purchase
Solve the first equation for r and substitute that into the second equation.
... r = 116 - g
... 3.79(116 - g) + 5.49g = 582.44 . . . . . use the expression for r
... 1.70g + 439.64 = 582.44 . . . . . . . . . simplify
... g = (582.44 -439.64)/1.70 = 84 . . . . subtract the constant, divide by 1.70
... r = 116 -84 = 32 . . . . . . . . . . . . . . . . . use the equation for r
32 regular reams and 84 recycled reams were purchased
An upper extreme is the highest number on the number line give. So the Upper extreme is 11
Answer:
234.3
Step-by-step explanation:
You use Law of Cosines:
a^2 = b^2 + c^2 - 2bc(cosA)
<em>Plug in the values</em>
a^2 = 400^2 + 375^2 - 2(400*375)(cos35)
a = sqrt(160000+140625-300000(cos35))
a = sqrt(300625 - 300000cos(35))
a is approx. 234.263498466, which rounds to 234.3