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Kitty [74]
3 years ago
8

ROBL0X IS DOWN PLEASE HELP IM GOING CRAZY

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

why is it down???

Step-by-step explanation:

hdhfnchcndud

Mademuasel [1]3 years ago
5 0

Answer:

ITSZ OKAYYY CALMM DOMWW

Step-by-step explanation:

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A teacher surveyed her class about their online accounts and wanted to know if they had “Fb” accounts or if they had “Snap ” acc
avanturin [10]

Answer:

a) 1/5

Step-by-step explanation:

There are 25 students total in the class.

If you look at the Venn Diagram, you can see that only 5 people have only "Fb" accounts.

Therefore, the probability that the person has a “Fb” account but not a “Snap” account is 5/25 or 1/5.

8 0
3 years ago
A study was conducted to investigate the effectiveness of hypnotism in reducing pain. An SRS of 8 subjects was randomly selected
chubhunter [2.5K]

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!

5 0
3 years ago
Pl help I will give you Brainly
elixir [45]

Answer:

The fourth one.

Step-by-step explanation:

I am pretty sure.

7 0
3 years ago
Please help me look at the attached picture
Lady bird [3.3K]

Answer:

Q(-10) = 299

Step-by-step explanation:

Q(x) = 3x^{2} - 1Q(-10) = 3(-10)^{2} - 1

Q(-10) = 3(100) - 1  (-10 to the second power is 100 (negative times a negative equals a positive)

Q(-10) = 300 - 1  3 times 100 equal 300

Q(-10) = 299

5 0
3 years ago
Graph 6x-2y=2 ,9x-3y=1
enot [183]

It's a linear function. We need only two points to draw a graph.

We choose any values of x and calculate the value of y.

6x-2y=2\qquad|-6x\\\\-2y=-6x+2\qquad|:(-2)\\\\y=3x-1

for x= 0 → y = 3(0) - 1 = 0 - 1 = -1 → (0, -1)

for x = 2 → y = 3(2) - 1 = 6 - 1 = 5 → (2, 5)

9x-3y=1\qquad|-9x\\\\-3y=-9x+1\qquad|:(-3)\\\\t=3x-\dfrac{1}{3}

for x = 0 → y = 3(0) - 1/3 = 0 - 1/3 = -1/3 → (0, -1/3)

for x = 2 → y = 3(2) - 1/3 = 6 - 1/3 = 5 2/3 → (2, 5 2/3)

4 0
3 years ago
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