What does 50 tens equal

Factor completly x^2 -64

Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

$\left(x+8\right)\left(x-8\right)$

Step-by-step explanation:

⇒ Given info:

Factor completely $x^2 -64$

⇒ Solution:

Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.

$=x^2-8^2$

Applying difference of two squares formula: $x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=x^2-8^2=\left(x+8\right)\left(x-8\right)\\$

$=\left(x+8\right)\left(x-8\right)$

Answer~: $\left(x+8\right)\left(x-8\right)$

xcookiex12

8/19/2022

7 0

2 years ago

|-4a+10|=2 solving absolute value eqations

Radda [10]

Answer:

a=2,3

Step-by-step explanation:

6 0

3 years ago

Please help asap will give brainliest!!!

Helga [31]

There is a 1/3 chance of the spinner hitting any letter then the next time it would be another 1/3 chance. You multiply these together and get 1/9 but this is not the answer because there is 1/9 of BOTH happening so you add 1/9 plus 1/9 and get 2/9. The answer is 2/9.

7 0

3 years ago

Read 2 more answers

Reduce 8/4 what is the lowest number

nika2105 [10]

The lowest number is 2/1 or 2.

reduce 8/4 to 4/2 which can be reduced to 2/1

4 0

3 years ago

Read 2 more answers

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago