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user100 [1]
3 years ago
10

the scale in a drawing is 2 in.:8 ft. On the drawing, a rolm is 3 inches long. What is the length in feet of the actual room?

Mathematics
2 answers:
Setler [38]3 years ago
6 0
I believe the length of the actual room would be 12 ft.

To figure this out, first find how many feet one inch represents.
8/2, or 4 feet. <
Then, we have 3 inches. Since 1 inch represents 4 feet, 3 inches must represent 12 feet, as 3*4=12.

Hope this helped! :)
Elina [12.6K]3 years ago
3 0
2 in: 8 ft simplifies to 1 in: 4 ft which is just generally easier to work with.

1 in: 4 ft = 3 in: x ft

x ft= 4*3 = 12

The length of the actual room is 12 feet.

Hope this helps!
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Consider the equation below.
vaieri [72.5K]

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6 0
3 years ago
The probability of Sandy flipping a coin twice and getting heads both times is 0.250.250, point, 25. The probability of John's s
Shkiper50 [21]

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they are the same.

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Plz help me i need help
natali 33 [55]
Ok so you know the first garden needs 1 and 2/5 bags of soil. Now first we need to find one fifth of that. So let's make this mied number into an improper fraction:

1 2/5 = 7/5

Ok now let's divide 7/5 by 5:

7/5 divided by 5/1 = 7/25

So Jared will need 7/25 bags of soil for his second garden, but we're STILL not done. now we have to add for the TOTAL.

1 2/5 + 7/25 > 7/5 + 7/25 > 7 x 5 = 35    > 35/25 + 7/25 = 42/25
                                           _________  
                                            5x 5 = 25

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8 0
3 years ago
Write the slope-intercept equation of the line parallel to 5y = 2x + 20 that goes through (-1, 3).
poizon [28]

The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:

y = (2/5)x + 4;

So the reference slope from the reference line is <span>m = 2/5;</span>.

Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line. 

Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);

Finally, y = (2/5)x + 17/5;


3 0
3 years ago
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