4c + 5h = 650 and
5c + 6h = 800 where c are chefs, h are helpers
Start by finding an expression for c
4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4
Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50
Take that 50 and substitute it into the expression we have for c to get a number value for c
C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100
Check your first equations, substituting $50 for the helpers and $100 for the chefs.
4 (100) + 5(50) =
400 + 250 = 650
5(100) + 6(50) =
500 + 300 = 800
Answer:
The slope is -1/3
Step-by-step explanation:
(y2-y1)/(x2-x1)
(4-5)/(6-3)
-1/3
Answer:
If oscar had 3 apples then he took 2 from Tim and gave 1 to Mike.How many apples does he have?
Step-by-step explanation:
Answer:
$20
Step-by-step explanation:
First we will change the ratio so that we are finding how much money Siti receives to the total amount of money.

Now we can solve for how much money Siti receives using a proportion.

We can see that the denominator increases 5 times, so the numerator must increase 5 times too. This means Siti receives $20.
Answer:
In inches, the radius of the can is <u>2</u>.
Step-by-step explanation:
Given:
The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.
Now, to find the radius of the can in inches.
Let the radius of can be 
Height of can = 
<em>As given, the number of cubic inches of the volume of the cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.</em>
<em><u>So, </u></em>
<em><u>Volume of can = lateral surface area of can.</u></em>
Now, we put formula of volume and lateral surface area of cylinder:


<em>Dividing both sides by </em>
<em> we get:</em>
<em />
<em />
<em />
<em />
<em>Dividing both sides by 6 we get:</em>

Therefore, in inches, the radius of the can is <u>2</u>.