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Masja [62]
3 years ago
14

Solve equation -2 • 4/5 = -3 1/2 • n

Mathematics
1 answer:
kogti [31]3 years ago
8 0
16/155 = n


explanation

A linear equation is an equation of a straight line. To solve linear equations, it is important to keep the following key concepts in mind:

Maintain balance of the equation by applying the same operations to both sides of an equation

Isolate for the variable by collecting like terms

Use inverse operations to rearrange an equation


to show your work

-8/ 5 = -31/2 • n
- 8/5 = -31n/2
2(-8/5) = 2 • -31/n
-16/5 = -31n
-16/5 / -31 = -31n/31
16/155 = n
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Answer:

48

240 ÷ 5 = 48

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8 0
2 years ago
Help?<br><br> a) 2/10 + 8/100<br> b) 13/100 + 4/10<br> c) 6/10 + 39/100<br> D) 70/100 + 3/10
Leni [432]

\green{––––––––––––––––––––––––––––––}

\huge\red{\boxed{\tt{{«ANSWER»}}}}

  • A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
  • B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
  • C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
  • D) 70/100 + 3/10 = <u>1</u>

<u>\green{––––––––––––––––––––––––––––––}</u>

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5 0
2 years ago
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Step-by-step explanation:

8 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

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