All categories

3 years ago

Which graph shows a system with an infinite number of solutions?

Mathematics

2 answers:

sukhopar [10]3 years ago

7 0

Answer:

The answer would be Graph C,

Graph A only has one solution which is where they intersect.

Graph B has no solution because they don't intersect, the lines are parallel to each other. If lines are parallel they don't have a solution.

However, Graph C the lines touch forever, as long as one of those lines don't curve they have an infinite number of solutions.

kotegsom [21]3 years ago

3 0

Graph A shows a single solution where the two lines cross paths. Graph B shows a case where there are no solutions as the lines will never touch. Graph C is the correct answer as it shows the two lines constantly intercepting each other, creating an infinite number of solutions.

You might be interested in

Can you please answer the question?

Roman55 [17]

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0

2 years ago

Write down the value of 10^-3

r-ruslan [8.4K]

Answer:

value of 10^-3= 0.001

hope it helps.

4 0

3 years ago

Read 2 more answers

Nestlé water pumps 1.2 million gallons per day out of G. Springs to put in bottles.

Delicious77 [7]

Answer:

3.2×10⁷ liters/week

Step-by-step explanation:

$\dfrac{1.2\cdot 10^6\,gal}{1\,day}\cdot\dfrac{7\,day}{1\,week}\cdot\dfrac{8\,pint}{1\,gal}\cdot\dfrac{1\,L}{2.11\,pint}=\dfrac{1.2\cdot 10^6\cdot 7\cdot 8\,L}{2.11\,week}\\\\\approx 3.2\cdot 10^7\,\dfrac{L}{week}$

5 0

3 years ago

Read 2 more answers

what if question is a passenger train travels at a speed of 72 km/h a man on the passenger train observes a goods train travelli

Nataly [62]

Answer: 35 m

Step-by-step explanation:

The problem is the same as:

a man is fix (not moving) and the goods train is travelling at the speed of 54+72 = 126 (km/h)

Distance = 126 km/h* 8 s=126000 m/(3600 s) * 8 s=35 m

4 0

3 years ago

Karen is seven years older than suzanne.Four years ago,karen was twice as old as suzanne was.How are they now?

Jlenok [28]

$x-\ Karen's\ age\\\\
y-\ Suzanne's\ age\\\\
 \left \{ {{x=y+7} \atop {x-4=2(y-4)}} \right.\\\\ \left \{ {{x=y+7} \atop {x-4=2y-8}} \right.\\\\ \left \{ {{x=y+7} \atop {x=2y-4}} \right.\\\\y+7=2y-4\ \ \ | subtract\ 2y\\\\
-y+7=-4\ \ \ | subtract\ 7\\\\
-y=-11\ \ \ | multiply\ by\ -1\\\\
y=11\\\\
x=11+7=18\\\\
Now\ Karen\ is\ 18\ years\ old \ and\ Suzanne\ is\ 11\ years\ old.
$

7 0

3 years ago