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3 years ago

9

Henry has two same size rectangle divided into the same number of equal parts.one rectangle has 2/5 of the parts shaded,and the

other has 1/2 of the parts shaded. Into how many parts could each rectangle be divided? show the work

2 answers:

marta [7]3 years ago

7 0

Answer:

4 times i think so sorry if im

wronge

Art [367]3 years ago

7 0

Answer:

Ya

Step-by-step explanation:

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Lisa is buying a computer for $1,500. The sales tax rate is 8.5%. Which expression should be used to calculate t, the total cost

Sveta_85 [38]

Answer:

<h3>t=$1627.5</h3>

Step-by-step explanation:

Step one:

given data

price of computer= $1500

sales tax= 8.5%

Step two

Let us compute the amount in tax

tax= 8.5/100*1500

=0.085*1500

=$127.5

Let the total cost be t

hence

t=1500+0.085*1500

t=1500+127.5

t=$1627.5

6 0

3 years ago

Use the equation k = x÷ y to find the constant of proportionality for the set of values

Lubov Fominskaja [6]

The constant of proportionality is 1/3

and three more values are

x 1 2 3 4 5

y 3 6 9 12 15

<h3>Variation</h3>

From the question, we are to determine the constant of proportionality

The given equation is

k = x ÷ y

From the given information,

When x = 1, y = 3

∴ k = 1 ÷ 3

k = 1/3

Thus, the constant of proportionality is 1/3

Now, we will determine the values of y for the values x = 3, x = 4, and x = 5

Since

k = x ÷ y

Then,

y = x ÷ k

When x = 3

y = 3 ÷ 1/3

y = 3 × 3

y = 9

When x = 4

y = 4 ÷ 1/3

y = 4 × 3

y = 12

When x = 5

y = 5 ÷ 1/3

y = 5 × 3

y = 15

Hence, the constant of proportionality is 1/3

and three more values are

x 1 2 3 4 5

y 3 6 9 12 15

Learn more on Variation here: brainly.com/question/19641181

#SPJ1

3 0

2 years ago

Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Since

$\\ f(36) = \frac{6}{25}$

And

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Then, the function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

8 0

3 years ago

Is 10x-7 equivalent to (7x-5)-(3x-2)

ValentinkaMS [17]

no, because (7x-5) - (3x-2) = 4x-3

This would, however, be true if the equation was (7x-5) + (3x-2), but since the equation is subtracting instead of adding the equation isn't equivalent to 10x-7.

3 0

3 years ago

Pls help i will give brainly!!!!!!

jasenka [17]

Answer:

$\frac{x^{2} }{10} -\frac{y^{2} }{15} = 1$

Step-by-step explanation:

since the foci is (±5,0), the standard form of the hyperbola would be $\frac{x^{2} }{a^{2} } -\frac{y^{2} }{b^{2} } = 1$

directics = ±a^2/c

±2 = ±a^2/5

a^2 = 10

a^2+b^2=c^2

b^2 = c^2-a^2 =5^2-10 = 15

7 0

3 years ago