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qwelly [4]
4 years ago
7

What is the first derivative of the following function: f(x) = aexp(-bx)

Mathematics
1 answer:
11Alexandr11 [23.1K]4 years ago
7 0

Answer:

The first derivative of the given function

\frac{df(x)}{dx} = - ab e^{-b x}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given f(x) = ae⁻ᵇˣ  ...( i )

we will use differentiation formula

\frac{d(e^{ax}) }{dx} = a e^{a x}

<em><u>Step(ii)</u></em>

Differentiating equation (i) with respective to 'x', we get

\frac{df(x)}{dx} = a e^{-b x} \frac{d}{dx} (-b x )

       = -ab e⁻ᵇˣ

\frac{df(x)}{dx} = - ab e^{-b x}

<u><em>Final answer:-</em></u>

The first derivative of the given function

\frac{df(x)}{dx} = - ab e^{-b x}

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Hello!

You go by the notation of the triangles

AB = PQ

Since both of them are the first two letters to label the triangles this is true
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<R = <C

Since they are both the last letter in the triangles this is also true
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<C = <P

They are not in the same place so this is not true
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<A = <Q

Since they are in different spots this is not true
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BC = PQ

Since they are in different spots this is also not true
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AC = QR

Since they are in different spots this is not true also
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The answers are A and B

Hope this helps!
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4 years ago
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What is X^2-X=0? It's factoring equations, but i'm not sure how to factor x-x=0, and then put it into curly brackets.
luda_lava [24]
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5 0
2 years ago
QUESTION 1 Evaluate −30 ÷ −6. a 5 b −5 c 6 d −6 QUESTION 2 Evaluate 62 ÷ (3 + 9). a3 b4 c12 d21 QUESTION 3 Danny made a mistake
Mashcka [7]

Answer:

A; ?; Line 3

Step-by-step explanation:

Question 1:

-30 divided by -6 is 5.

The negatives cancel each other out.

And 30 divided by 6 is simply 5.

Question 2:

62\div(3+9)

Do the operation inside the parenthesis first:

62\div12

Divide. 12 does not go into 62 evenly. 12 times 5 is 60, so the answer is 5 remainder 2:

62\div12=5\text { R}2

Or in fractions:

31/6

(Was there a typo? From what you've given me, the correct answer is not listed.)

Question 3:

So we have to following steps:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+11(2)\\\text{Line 4: }21+22\\\text{Line 5: }43

The mistake is in Line 3. Danny cannot just combine 5+6(2) into 11(2). Instead, he should multiply 6(2) and then add. Thus, the correct solution is:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+5+12\\\text{Line 4: }26+12\\\text{Line 5: }38

3 0
3 years ago
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