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nadezda [96]
3 years ago
12

Write the standard form of the equation of the circle with its center at (-5,0) and a radius of 8 what is the equation of the ci

rcle in standard form
Mathematics
1 answer:
Leto [7]3 years ago
7 0

Answer:

\large\boxed{(x+5)^2+y^2=64}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the center (-5, 0) and the radius r = 8. Substitute:

(x-(-5))^2+(y-0)^2=8^2\\\\(x+5)^2+y^2=64

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Answer:

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Step-by-step explanation:

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2 years ago
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You are building a scale model of a fishing boat. The boat is 62 ft long and 23 ft wide. The
Temka [501]

The wide of the model should be approximately 5.194 inches

Step-by-step explanation:

You are building a scale model of a fishing boat

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We need to find how wide should it be

∵ The boat is 62 feet long

∵ The model of the boat is 14 inches long

- That means 14 inches represents 62 feet

By using the ratio method

→ Actual (ft)    :    Model (in)

→ 62               :    14

→ 23               :     x

By using cross multiplication

∵ 62 × x = 23 × 14

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∴ x ≅ 5.194

∵ x represents the wide of the model

∴ The wide of the model is approximately 5.194 inches

The wide of the model should be approximately 5.194 inches

Learn more:

You can learn more about the scale drawing in brainly.com/question/570757

#LearnwithBrainly

5 0
3 years ago
The weight of an empty pickup truck is 2.1 times the weight of an empty car. If the empty car weighs 1.8 tons, how many tons doe
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What is the general form of the equation for the given circle centered at o (0,0) (4,5)?
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The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to <span>(x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41</span>
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Solve for x: −5|x + 1| = 10
Elena-2011 [213]

|a|\geq0\ for\ a\in\mathbb{R}\\\\|a|=a\ for\ a\geq0\\\\|a|=-a\ for\ a

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3 years ago
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