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kirill115 [55]
3 years ago
7

If f(x)= x^3-2x^2 which expression is equivalent to f(I)

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0
Factor:

x^6-2x2

Answer:

x^2(x^4-2)
You might be interested in
One end of a ramp is raised to the back of a truck 5 feet above the ground. 1 point
sveta [45]

Answer:

38.7°

Step-by-step explanation:

You are basically looking at a triangle with a 90° angle (check picture).

Since we are looking for the ramp's angle and are given the length of the opposite and the hypothenuse, we have to solve the following equation:

sin (\alpha) = opposite / hypothenuse= 5 ft/8ft

which is equivalent to

\alpha = sin^{-1}(5/8)\approx 38.7\deg

6 0
3 years ago
Jessica paid $5 toward a $20 ticket this month. What decimal represents the fraction she paid?
CaHeK987 [17]

Answer:

b 0.25

Step-by-step explanation:

20 ÷ 5 = 4 so 1/4 of 20 or 0.25 is 5

4 0
3 years ago
Read 2 more answers
Can someone please help me? :(
den301095 [7]

Answer:

a=(0,0)

Step-by-step explanation:

i actually dont know but thnks for the points BTW

4 0
3 years ago
Please answer quickly!
Digiron [165]

Answer:

Hi there, the answer is 1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The Office of Student Services at UNC would like to estimate the proportion of UNC's 28,500 students who are foreign students. I
ANEK [815]

Answer:

For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.061, n = 50

So

Mean:

\mu = p = 0.061

Standard deviation:

s = \sqrt{\frac{0.061*0.939}{50}} = 0.034

For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.

3 0
3 years ago
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