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dangina [55]
3 years ago
7

A scale drawing of a rectangular parking lot is shown. The width of the parking lot is shorter than the length. The actual width

is 48 feet. Based on the scale drawing, what is the length, in feet, of the actual parking lot?
Mathematics
2 answers:
nika2105 [10]3 years ago
6 0

Answer:

15ft

Step-by-step explanation:

When you divide the length of the drawing by the length of the real one you will find the scale factor. Every one cm in the drawing is 15 ft. in the real one.

insens350 [35]3 years ago
4 0

Answer:

The length of the actual parking lot is 192 feet

Step-by-step explanation:

Scale drawing is a type of drawing that involves the used of a scale to reduced or enlarged the size of a given object or shape. The drawing is an application of reduced scale. All  dimensions in the drawing are in centimeters, while in the actual dimensions are in feet.

In the drawing, the width is 3.2 cm, while the actual width is 48 feet.

The rate = \frac{48}{3.2}

              = 15

Thus the scale used is:      1 cm = 15 feet .

The actual length of the parking lot = length in the drawing × 15

                                                           = 12.8 × 15

                                                           = 192 feet

Therefore, the actual length of the parking lot is 192 feet.

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Consider the system of equations.
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The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

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The given system of equations:

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-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

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x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

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The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

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