The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821
<h3>How to solve?</h3>
Given: currently has seven rackets of each version.
Then the probability that the next ten customers get the racket they want is P(3≤X≤7)
<h3>Why P(3≤X≤7)?</h3>
Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.
X ~ Binomial (n = 10, p = 0.6)
P(3≤X≤7) = P(X≤7) - P(X≤2)
From Binomial Table:
= 0.8333 - 0.012
= 0.821
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3 is the first one.
-1 is the 2nd
and 7 is the 3rd
The limits to the given function are as follows:
1. ∞
2. -∞
3. ∞
4. 1
5. -∞
<h3>What is a limit?</h3>
A limit is given by the <u>value of function f(x) as x tends to a value</u>.
For this problem, at x = 0, we have that to the left the function goes to positive infinity, while to the right it goes to negative infinity, hence:
1. lim f(x) = ∞
x->0-
2. lim f(x) = -∞
x->0+
At x = 2, the function goes to infinity to the left and to the right, hence:
3. lim f(x) = ∞
x->2
To the left of the graph, the function goes to negative infinity, while to the right it goes to 1, hence:
4. lim f(x) = 1
x-> ∞
5. lim f(x) = -∞
x-> -∞
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Answer:
Solving equation i and ii, we get;
3x-3y+x+3y=9+12
4x=21
x=21/4
Putting the value of x in equation ii.
(21/4)+3y=12
3y=12-(21/4)
3y=(48-21/4)
y=27/(4*3)
y=9/4