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kogti [31]
3 years ago
7

Use property to find sum pr product 8×51

Mathematics
2 answers:
aleksley [76]3 years ago
7 0
If you take 8 and multiply it by 51 then you get 408. (1 times 8 is 8 then 5 times 8 is 40 and put them next to each other it's 408)
aksik [14]3 years ago
3 0

8 × 51 = 408

Eight times fifty-one equals four hundred eight

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Please helppp please help
irga5000 [103]

Answer:

a. parallel    b. neither      c. neither      d. perpendicular

Step-by-step explanation:

Find the gradient of the line in the graph

Choose 2 coordinates, I choose (0,1) and (3,3)

Use the formula

(y2 - y1)/(x2 - x1)

(3 - 1) / (3 - 0)

2/3

Gradient of a parallel line is the same

Gradient of a perpendicular line formula m1m2 = -1

(2/3)m2 = -1

m2 = -3/2

The gradient of the perpendicular line will be -3/2

The gradient of the parallel line will be 2/3

Any other gradient will be neither parallel nor perpendicular.

3 0
2 years ago
AREA OF A CIRCLE PLS HELP​
sweet [91]

Answer:

153.86 ft²

Step-by-step explanation:

Area = \pi r^2

= 3.14 * 7 * 7

= 153.86 ft²

8 0
3 years ago
Read 2 more answers
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
SinX/1-cosX+sinX/1+cosX
d1i1m1o1n [39]
It looks like you're missing some parentheses.
I think this is the equation you mean:
sin(x)/(1-cos(x)) + sin(x)/(1+cos(x))
your common denominator is (1-cos(x))*(1+cos(x)), which is the difference of squares simplification and is equal to (1-cos^2(x)) = sin^2(x)
Numerator: sin(x)*(1+cos(x)) + sin(x)*(1-cos(x))
= sin(x) +sin(x)cos(x) + sin(x) - sin(x)cos(x)
= 2sin(x)
Answer: 2sin(x)/sin^2(x) = 2/sin(x) = 2csc(x)
3 0
4 years ago
Graph y=4sin pi/4 (x+3)+1
Shtirlitz [24]
Where is the graph????
5 0
3 years ago
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