All categories

2 years ago

Find the missing side. Round to the nearest tenth.

Mathematics

1 answer:

Firdavs [7]2 years ago

5 0

Answer: 23.7

Step-by-step explanation:

Let's calculate the acute angle at the base of the triangle:

180° - 90° - 40° = 50°

Find side x:

$\dfrac{sin \: 90^{o} }{31} =\dfrac{sin \: 50^{o} }{x}\\\\sin \: 90^{o} \cdot x=sin \: 50^{o} \cdot 31\\\\sin \: 90^{o} =1\\sin \: 50^{o} \approx 0.766\\1 \cdot x =0.766 \cdot 31\\x=23.746\\23.746 \approx 23.7$

You might be interested in

Your income last year was $27,000 from your main job, $2,200 from a part time job and $600 from interest earned on investments.

kotegsom [21]

Answer:

$894

Step-by-step explanation:

$27,000+$2,200+$600= $29,800

$29,800*0.03=$894

5 0

3 years ago

Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a

Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

$P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}$

(a). Exactly one face up is red.

The odds of only the first die being red are:

$P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}$

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

$P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}$

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

$P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}$

The probability that all die turn up red is:

$P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}$

Thus, the probability that at least one die turns up red is:

$P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}$

4 0

3 years ago

What conclusion can you draw about 1 cubic centimeter and 1 mL?

forsale [732]

Answer:

They represent the same magnitude of volume

Step-by-step explanation:

1cc (cubic centimeter) is equal to 1 mL (millilitres)

6 0

2 years ago

Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target clos

Masteriza [31]

Either way. The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

...

Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121 (≈0.0259 or 2.6%)

P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)

6 0

3 years ago

Does anyone know how to turn these fractions into percents??? please help!!!

belka [17]

You divide the fractions to get percents

4 0

3 years ago