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Harlamova29_29 [7]
3 years ago
12

Find the highest common factor of 1080, 1188 and 1815.

Mathematics
2 answers:
Julli [10]3 years ago
7 0

Answer:

The highest/greatest common factor of 1080, 1188, and 1815 is 3. :)

Step-by-step explanation:

When I was 30, I was bit by a child and bit it back

defon3 years ago
5 0

Answer:

The highest/greatest common factor of 1080, 1188, and 1815 is 3. :)

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John buys a computer on sale for $450.00. He
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First you can add 50 dollars to 450 dollars which is 500 then divide that 500 by 2 and that is 250
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2 years ago
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Solve: X=4+(4x-4)
11111nata11111 [884]

Answer:

answer is 10

Step-by-step explanation:

3 0
4 years ago
Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

C = $62.46

5 0
3 years ago
6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi
Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of p = 1 - 0.85 = 0.15

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

So

P = 0.15P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597

So

P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390

3.90% probability that the third failure will occur on the tenth component tested

5 0
3 years ago
A pile of sand has a weight of 90kg.
ankoles [38]

Answer:

9Kg, 18Kg and 63 Kg

Step-by-step explanation:

Sum the parts of the ratio, 1 + 2 + 7 = 10 parts

Divide the weight of sand by 10 to find the value of one part of the ratio

90 Kg ÷ 10 = 9 Kg ← value of 1 part of the ratio, thus

2 parts = 2 × 9 Kg = 18 Kg

7 parts = 7 × 9 Kg = 63 Kg

Thus the weights of each bag are 9 Kg, 18 Kg and 63 Kg

3 0
3 years ago
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