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Scrat [10]
3 years ago
12

Please help me ASAP!!

Mathematics
2 answers:
Veronika [31]3 years ago
8 0
The answer should be summer and fall, if that’s not it then it is winter and spring.
ohaa [14]3 years ago
5 0
Summer and fall because they are almost half of the histogram.
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Find the slopes of the line represented by each table of values
irga5000 [103]
Find two pefect lines that touches the middle then do rise over run and that will be your slope
3 0
3 years ago
Read 2 more answers
What are the properties of the point (2, 0) in this graphed function?
Alex73 [517]

The point (2,0) represents a relative minimum and an x-intercept.

<h3>How to determine the property?</h3>

The missing graphed function is added as an attachment

The point (2,0) means that:

x = 2 and y = 0

On the attached graph, we can see that the graph touches the x-axis at (2,0); this represents the x-intercept

Also, the graph has a minimum at (2,0); this represents the relative minimum

Hence, the point (2,0) represents a relative minimum and an x-intercept.

Read more about  graphed functions at:

brainly.com/question/4025726

#SPJ1

5 0
2 years ago
HELP!!!!!
podryga [215]
Solve for the x-max or h :\
-b/(2a)=-8/(2*-2)=2=k
plug it in to equation to get k:/
y(2)=-2(2)^2+8(2)+3
-8+16+3=11=k
y=a(x-2)^2+11&#10;
solve for a by pluging (0,0)
then a= -11/4
y=-11/4(x-2)^2+11

8 0
4 years ago
What is the quotient of 7^-1/7^-2?<br> 1/343<br> 1/7<br> 7<br> 49
vazorg [7]

Answer:

7^-1/7^-2

7^(-1+2)=7^1=7

8 0
3 years ago
Show all work and reasoning
Natalija [7]
Split up the interval [2, 5] into n equally spaced subintervals, then consider the value of f(x) at the right endpoint of each subinterval.

The length of the interval is 5-2=3, so the length of each subinterval would be \dfrac3n. This means the first rectangle's height would be taken to be x^2 when x=2+\dfrac3n, so that the height is \left(2+\dfrac3n\right)^2, and its base would have length \dfrac{3k}n. So the area under x^2 over the first subinterval is \left(2+\dfrac3n\right)^2\dfrac3n.

Continuing in this fashion, the area under x^2 over the kth subinterval is approximated by \left(2+\dfrac{3k}n\right)^2\dfrac{3k}n, and so the Riemann approximation to the definite integral is

\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n

and its value is given exactly by taking n\to\infty. So the answer is D (and the value of the integral is exactly 39).
8 0
4 years ago
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