Answer:
x=8
Step-by-step explanation:
If the value of x varies directly as the value of y we can say they are directly proportional. This implies that when y increases x will increase too, and when y decreases x will also decrease.
If x=16 when y=3/4 we can write their relation as:
x/y = 16/(3/4) = 16*(4/3) = 64/3
So, for every value of y, the ratio x/y must maintain equal to 64/3 because both values are proportional.
Now we can see what happens to x when y varies. If y=3/8:
x/(3/8) = 64/3
Multiply both sides by 3/8 to eliminate the 3/8 in the denominator.
x/(3/8) * (3/8) = (64/3) * (3/8)
See that we have a 3 multiplying and another dividing, we can eliminate them.
x = 64/8
x = 8
So, if y decreases to 3/8 x will decrease to 8. Notice that y is decreasing in a half as 3/8 is the half of 3/4, and x is also decreasing in a half from 16 to 8, what makes sense.
Answer:
Vertical A @ x=3 and x=1
Horizontal A nowhere since degree on top is higher than degree on bottom
Slant A @ y=x-1
Step-by-step explanation:
I'm going to look for vertical first:
I'm going to factor the bottom first: (x-3)(x-1)
So we have possible vertical asymptotes at x=3 and at x=1
To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)
3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3
Let's check x=1
1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also
There is no horizontal asymptote because degree of top is bigger than degree of bottom
There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)
x -1
--------------------------------------------------
x^2-4x+3 | x^3-5x^2+4x-25
- ( x^3-4x^2+3x)
--------------------------------
-x^2 +x -25
- (-x^2+4x-3)
---------------------
-3x-22
So the slant asymptote is to x-1
Answer:
105 miles in 3 hours
Step-by-step explanation:
Your Welcome
You have not given any graphs to choose from but x=-3 would be the graph that has a vertical line running through every point that has -3 as an x coordinate and would cross the x axis (the horizontal axis) at -3
Answer and explanation:
The wrong step <u>is changing the sign in step 2</u>
Such that; in step 1 the student had; (x + 6) and (x - 2)
In step 2, the student should have;
x + 6 = 0 and x - 2 = 0 instead of x - 6 = 0 and x + 2 = 0
Step 3, will thus be;
x = -6 and x = 2
