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antiseptic1488 [7]
3 years ago
6

At the baby next checkup the baby weighed 11 pounds and four ounces how many ounces did the baby gain since the appointment ment

ioned in the first probloem
Mathematics
1 answer:
V125BC [204]3 years ago
3 0

Answer:

The baby weighs 8 pounds.

Step-by-step explanation:

Since there are 16 ounces in 1 pound, you divide 128 by 16 to get 8.

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Which expressions are equivalent to 5 x-15? Select three options.
mojhsa [17]

Answer:

b) 5 (x-3)\\c) 4 x + 3 y-15- 3 y + x\\e) -20 - 3 x + 5 + 8 x

Step-by-step explanation:

We are given the following expression in the question:

5x-15

a)

5 (x + 15)\\=5(x) + 5(15)\\=5x + 75

which is not equivalent to the given expression.

b)

5 (x-3)\\=5(x)-3(5)\\=5x-15

which is equivalent to the given expression

c)

4 x + 3 y-15- 3 y + x\\=4x+x+3y-3y-15\\=5x-15\\=5(x-3)

which is equivalent to the given expression.

d)

-7 y-6 x- 8 y + x\\=-7y-8y-6x+x\\=-15y-5x\\=-5(x+3y)

which is not equivalent to the given expression.

e)

-20 - 3 x + 5 + 8 x\\=-3x+8x-20+5\\=5x-15

which is equivalent to the given expression.

7 0
3 years ago
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N76 [4]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If a = -9 and b = 4, what is the value of a + b ?<br> A. -5<br> B. 5 <br> C. -13 <br> D. 13
madreJ [45]

Answer:

A. -5

Step-by-step explanation:

-9 + 4 = -5

hope this helps

7 0
3 years ago
It is believed that 3% of people actually have this predisposition. The genetic test is 99% accurate if a person actually has th
fiasKO [112]

Answer:

Required Probability = 0.605

Step-by-step explanation:

Let Probability of people actually having predisposition, P(PD) = 0.03

Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97

Let PR = event that result are positive

Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99

Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02

So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)

Using Bayes' Theorem to calculate above probability;

 P(PD/PR) = \frac{P(PD)*P(PR/PD)}{P(PD)*P(PR/PD)+P(PD')*P(PR/PD')}

                   = \frac{0.03*0.99}{0.03*0.99+0.97*0.02} = \frac{0.0297}{0.0491} = 0.605 .

7 0
3 years ago
The domain of g(x) =(x+1)(2x-5) is (-4,-2,01) what is the range
lions [1.4K]

Answer:

D: {-4, -2, 1}

R: {39, 9, -10}

Step-by-step explanation:

7 0
3 years ago
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