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2 years ago

Can smbody help me out?

Mathematics

1 answer:

Alex777 [14]2 years ago

3 0

Answer:

C. 30(-2)= -60 is the correct answer

Step-by-step explanation:

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Please help!! Quickly

irina [24]

Answer:

The answer to your question is: a = 3.5 units

Step-by-step explanation:

Right triangle

to find a we need to use the trigonometric function cosine

cosine Ф = opposite leg / hypothenemus

Clear opposite leg from the equation

opposite leg = hypothenemus x cosine Ф

a = opposite leg = 5 x cosine 45

a = 5 x 0.70

a = 3.5 units

7 0

3 years ago

Which choices are equivalent to the expression below

arsen [322]

Answer:

Gotta give the image

Step-by-step explanation:

Bdndbdjddbdhd dvdn d dbd

4 0

2 years ago

Use the figure to complete the proportion.

MAVERICK [17]

Answer:

BE / AB = HE / AH

Step-by-step explanation:

AE is angle bisector

BE / HE = AB / AH

BE / AB = HE / AH

6 0

3 years ago

It cost Alexandra $9.90 to send 198 text messages. How many text messages did she send if she spent $2.35?

tatiyna

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

2 years ago