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mrs_skeptik [129]
3 years ago
4

Mai has a piece of cloth that is 8.35 meters long. How many 15-centimeter pieces can she cut from the cloth ? How much will be l

eft over
Mathematics
1 answer:
Daniel [21]3 years ago
0 0
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I need help with my math problems
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7 0
3 years ago
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PLEASE HELP I WILL MARK BRAINLIST!!
marshall27 [118]

14: \frac{1}{2} = \frac{8}{1}    \frac{x}{y} = \frac{56}{1}

56/8 = 7 so multiply 1/2 by 7/1 to get the unidentified fraction "x/y"

1/2 · 7/1 = 7/2 or 3 1/2

15.  \frac{2}{5} = \frac{x}{100}

to get from 100 to 5, you would divide by 20, so to solve for x, multiply 2 by 20, to get a product of 40.

40/100 = 40% or D

16. \frac{3}{5} = \frac{12}{x}

A

7 0
3 years ago
36. The price of a new home. According to the U.S. Census
zmey [24]

Answer:

210

Step-by-step explanation:

because you use 13.% divided by the price

4 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
A water tank is 5m tall and has a diameter of 3,5m. Calculate the capacity (volume) of the tank. Use pi=3,14
aleksandr82 [10.1K]

Answer:

<h2>10000000000000</h2>

Step-by-step explanation:

<h2>minions </h2>
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