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3 years ago

Simplify (4b+7)8b^2 Can someone help me please?

Mathematics

2 answers:

vredina [299]3 years ago

8 0

Answer:

32b^3+56b^2

Step-by-step explanation:

distribute 8b^2 through the ()

32b^3+56b^2

Fed [463]3 years ago

7 0

Answer:

$32b^{3} +56b^{2}$

Step-by-step explanation:

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HELP PLEASE. A pizza shop charges customers based on the area of the pizza they order. The cost of a pizza in dollars can be rep

san4es73 [151]

For this case we have that the cost of each pizza is given by the following function:

$S (r) = 0.1 \pi * r ^ 2$

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We cleared the radius, using $\pi = 3.14$ :

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So, the radius of the pizza is $9.16 \ in$

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3 years ago

Read 2 more answers

There are 8 tennis players in a round robin tournament, which means each team will play every other team once. How many matches

Aliun [14]

<h3>Answer: 28</h3>

==========================================================

Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

----------------------------------

Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

----------------------------------

Method 3

Use the nCr combination formula with n = 8 and r = 2

$n C r = \frac{n!}{r!(n-r)!}\\\\8 C 2 = \frac{8!}{2!*(8-2)!}\\\\8 C 2 = \frac{8!}{2!*6!}\\\\8 C 2 = \frac{8*7*6!}{2!*6!}\\\\ 8 C 2 = \frac{8*7}{2!}\\\\ 8 C 2 = \frac{8*7}{2*1}\\\\ 8 C 2 = \frac{56}{2}\\\\ 8 C 2 = 28\\\\$