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kiruha [24]
3 years ago
11

Ken predicts that the average temperature will be-5C in Decjember. If he predicts the temperature will rise 6 C in January and f

all 3 C in February,which of the following equations can he use to fin. the sum of the temperatures for those months?
Mathematics
2 answers:
Andrews [41]3 years ago
5 0

Answer:

-5+6-3

Step-by-step explanation:

DUH!!!!!

frozen [14]3 years ago
5 0

Answer:  

[(–5) + (–3)] + 6 = –2 and [6 + (–5)] + (–3) = –2

Step-by-step explanation:

DUH!! (as one guy said) this time im right tho.

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A city's population was 30,200 people in the year 2010 and is growing by 950 people a year. Give a formula for the city's popula
kolbaska11 [484]

the formula should look like this:

 p=30200+950t

3 0
3 years ago
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Beverly drove from the Atlantic City to New York she drove 284 miles at a constant speed of 58 mph how long did it take Beverly
lubasha [3.4K]

Answer:

4.9 hours = 4 hours 54 minutes

Step-by-step explanation:

speed = distance/time

time * speed = distance

time = distance/speed

time = (284 miles)/(58 mph) = 4.9 hours

4.9 hours - 4 hours = 0.9 hours

0.9 hours * (60 minutes)/(1 hour) = 54 minutes

4.9 hours = 4 hours 54 minutes

8 0
3 years ago
Please help, Algebra 1
Svetach [21]
3px = 2q(r-5x)
distribute
2qr - 10qx
3px = 2qr - 10qx

To solve for x
add 10qx to both sides
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factor out x
x(3p+10q) = 2qr
divide both sides by 3p+10q to isolate x
x = 2qr / <span>(3p+10q)

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3 years ago
What’s the vertex of the graph of the function y=x^2-8x+12
myrzilka [38]

Answer:

The vertex is 4

6 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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