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romanna [79]
3 years ago
12

Can someone pls help me.. thanks <3 Factor 15x^2y^2-3x^3y+75x^4 Show your work.

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

3(x^y(5x^2y-x³)+25x⁴))

Step-by-step explanation:

15x^2y²-3x^3y+75x⁴

From 15x^2y²-3x^3y only, 3x^y is the common factor

=> 3x^y(5x^2y-x³)+75x⁴

Taking the common factor of the latter expression, 3 shows to be the common factor of all the expression.

=> 3(x^y(5x^2y-x³)+25x⁴)

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MA_775_DIABLO [31]

Answer: 58/9

Step-by-step explanation:

5 0
3 years ago
Solve each system using the substitution method.
san4es73 [151]
-2x+3(x-1) = -6
-2x + 3x - 3=-6
x-3 = -6
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x= -3
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7 0
4 years ago
I need help with these problems ASAP
svetoff [14.1K]
3 is $16! Hope I helped
8 0
4 years ago
Read 2 more answers
Find CE if AE = 8 and BC = 3. Round to the nearest tenth. AE is tangent to the circle. (Hint: May need quadratic formula)
boyakko [2]

The value of CE = 18.3

According to the statement

Here we have given the value of tangents AE = 8 and BC = 3

we have to find the value of CE and

It is given that AE is the tangent to the circle.

Now we make a equation to find the CE then

(8)^2 = 3(x+3)

In this equation the value of AE is 8. and

In this x is the value of CE and BC have value 3.

And the total value of BE becomes the 3(x+3) and 3 is the parts by which  BE is formed.

Then solve the equation

64= 3x +9

3x = 64-9

x = 18.3

So, The value of CE = 18.3

Learn more about TANGENT here brainly.com/question/17040970

#SPJ1

7 0
2 years ago
Please answer correctly !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
8090 [49]

Answer:

acute = 30,right angle = 90,obtuse = 135,line = 180

7 0
4 years ago
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