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Fofino [41]
3 years ago
7

As part of a screening process, computer chips must be operated in an oven at 145 °C.

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

the answer is 77 degrees celcius

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What should be true about -5 and 5? Why?
Law Incorporation [45]
The thing that is true about -5 and 5 is the answer is zero.
5 0
3 years ago
The stemplot displays the selling prices of homes for ABC Realty in April.
Alexxandr [17]

The stemplot displays the entire values for the selling prices of homes for ABC Reality in April.

The correct set of data for the stemplot is the option;

  • <u>$459,000, $227,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000</u>

<h3>Method by which the above option is selected</h3>

The data in the stemplot are;

459,000, 482,000, 213,000, 225,000, 276,000, 277,000, 287,000, 123,000, 181,000, 181,000, 196,000, 67,000, 85,000, 92,000

Given that there are no values in the 300,000s, and that 181,000 appear twice, the option that corresponds to the above data is therefore;

  • $459,000, $277,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000

Learn more about stemplot here:

brainly.com/question/10572086

6 0
2 years ago
A.0.5×10^4
Juliette [100K]

Answer:

sdd

Step-by-step explanation:

3 0
3 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
A football team played A games last year. They lost B of those games. What was their winning percentage? 
Alexeev081 [22]
Winning%=100[wins/(total games)]

w%=100(A-B)/A

So the way that your choice expressed that is:

(A-B)/A x 100
7 0
3 years ago
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