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KengaRu [80]
3 years ago
12

Determine the equation of the linear function that has a slope of -4 and passes through the point (2,-4). Write the equation in

slope-intercept form and draw/graph the equation

Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

Part 1) y=-4x+4

Part 2) The graph in the attached figure

Step-by-step explanation:

Part 1)

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=-4\\point\ (2,-4)

substitute in the linear equation

-4=-4(2)+b

solve for b

-4=-8+b\\b=8-4\\b=4

substitute

y=-4x+4

Part 2) Draw the equation

we know that

To graph a line we need two points

we have the y-intercept (0,4) and (2,-4)

Plot the points, connect them and join to draw the line

see the attached figure

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The inequality that describes this graph of the number line is x ≥ 4

<h3>How to determine the inequality that describes this graph?</h3>

From the question, we have the following properties:

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The property 3 above implies that the domain of the number line is the set of all real numbers.

The property 4 above implies that the inequality of the number line is a greater than or equal to inequality, and the value starts from 4

This is represented by the following inequality

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Read 2 more answers
The Tucker Gym charges a one time fee of $50 plus a $25 monthly membership
FinnZ [79.3K]

Answer:

y = 50 + 25x.............(i)

y = 80 + 15x.............(ii)

x = 3

y = 125

Step-by-step explanation:

The tucker Gym charges a one time fee of $50 plus a $25 monthly membership charge.  

The NoFo health club charges a one time fee of $80 plus a $15 monthly membership fee.

Let

number of month = x

total cost = y

Tucker Gym

y = 50 + 25x.............(i)

NoFo Gym

y = 80 + 15x.............(ii)

combining the equation

y = 50 + 25x.............(i)

y = 80 + 15x.............(ii)

y - 50 = 25x

y/25 - 2 = x

insert x in equation (ii)

y = 80 + 15(y/25 - 2)

y = 80 + 3y/5 - 30

y = 50  + 3y/5

y - 3y/5 = 50

5y - 3y/5 = 50

2y/5 = 50

cross multiply

2y = 250

y = 250/2

y = 125

insert y in equation (i)

125 = 50 + 25x

125 - 50 = 25x

75 = 25x

x = 75/25

x = 3

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