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Phoenix [80]
2 years ago
12

Repost of my question i need help quicklyy help plzz

Mathematics
1 answer:
GuDViN [60]2 years ago
8 0

Answer:

According to logarithmic properties.... The right hand side can be written as

log base 7 (180/3).....which is log base 7 60

So according to the question cancel out the log base 7 from both sides....

Then we get 8r + 20 = 60

That is 8r = 40..

That is r = 5......

Therefore the value of r is 5

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Solve -3(-2x+20)=-8(x+12)+92 please?
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The answer is x=4 hope it helps
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If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2.<br><br> 1<br> 2<br> 9
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I think that the answer would be 2 if I am right 
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Read 2 more answers
A house was valued at $100,000 in the year 1987. The value appreciated to $165,000 by the year 2002.
iris [78.8K]

Answer:

  A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.

  B) 3.39% per year

  C) $182,000

Step-by-step explanation:

A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.

  165000 = 100000(1 +r)^15

  1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root

  1.03394855265 -1 = r ≈ 0.0339

The value was multiplied by about 1.0339 each year.

__

B) The value increased by about 3.39% per year.

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C) S = $100,000(1.03394855265)^18 ≈ $182,000

8 0
3 years ago
Which statement is true about this equation? -9(x-3)+12=-3(2x+5)-3x
Finger [1]

Answer:

Any value of "x" makes the equation true

Step-by-step explanation:

(-∞,∞)

All real numbers

i hope this work for you

8 0
2 years ago
45 points! Please help!
Tju [1.3M]

Answer:

Sequence One

Step-by-step explanation:

S = a₁ / (1 − r) is the infinite sum of a geometric series where |r| < 1.

Sequence One: r = 1/5

Sequence Two: r = 2

Sequence Three: not geometric

Sequence Four: r = -3/2

Only Sequence One has |r| < 1.

5 0
3 years ago
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