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nirvana33 [79]
3 years ago
9

How do you identify the min and max of parabolas

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0
Identify<span> the vertex, axis of symmetry, and </span>min/max<span> value of each</span>
Dima020 [189]3 years ago
8 0
The min is the lowest point of a parabola and the max is the highest point. If it looks like a "U" then you're looking for the minimum whereas if it looks like an "n" you're looking for the maximum
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Find the maximum value of P=3x+2y subject to the following constraints:<br> Please help me!!!
UkoKoshka [18]

Answer:

maximum value of P is 33

Step-by-step explanation:

Sketch the lines represented by the constraints

5x + y = 16

with intercepts (\frac{16}{5}, 0) and (0, 16)

2x + 3y = 22

with intercepts (11, 0) and (0, \frac{22}{3})

The solutions to both are below the lines.

Solve 5x + y = 16 and 2x + 3y = 22 simultaneously to find the point of intersection at (2, 6)

The coordinates of the vertices of the feasible region are

(0, 0), (0, 16), (2, 6), 11, 0)

Evaluate the objective function at each vertex

P = 3(0) + 2(0) = 0 + 0 = 0

P = 3(0) + 2(16) = 0 + 32 = 32

P = 3(2) + 2(6) = 6 + 12 = 18

P = 3(11) + 2(0) = 33 + 0 = 33

The maximum value of P is 33 when x = 11 and y = 0

6 0
3 years ago
Answer quick for brainliest &lt;3
Brut [27]

Answer:

4mph

Step-by-step explanation:

just look at the graph

7 0
3 years ago
Which is a good comparison of the estimated sum and the actual sum of 7 7/8 + 2 11/12?
Amanda [17]

Answer:

D

*thinking*

you would assume that it is 11 the actual is  10 19/24

Wich is not quite 11

3 0
3 years ago
Read 2 more answers
Use the distance formula to find the area of the rectangle
nasty-shy [4]

Answer:

Therefore Area of Rectangle is 50 unit².

Step-by-step explanation:

Given:

Let the vertices of a Rectangle be

A ( -1 , 7)

B ( 4 , -3)

C ( 0 , -5)

D ( -5 ,5)

To Find:

Area of Rectangle ABCD = ?

Solution:

First we will find the Length and Width of Rectangle by Distance Formula ,

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting the values we get

l(AB) = \sqrt{((4-(-1))^{2}+(-3-7)^{2} )}

l(AB) = \sqrt{((5)^{2}+(-10)^{2} )}\\l(AB)=\sqrt{125}=5\sqrt{5}\ unit

Similarly for BC we will have,

l(BC) = \sqrt{((0-4)^{2}+(-5-(-3))^{2} )}\\l(BC)=\sqrt{20}=2\sqrt{5}\ unit

Now

Length=AB =5\sqrt{5}\ unit\\Width=BC=2\sqrt{5}\ unit

Now Area of Rectangle is given by

\textrm{Area of Rectangle}=Length\times Width

Substituting the values we get

\textrm{Area of Rectangle ABCD}=5\sqrt{5}\times 2\sqrt{5}=10\times 5=50\ unit^{2}

Therefore Area of Rectangle is 50 unit².

4 0
3 years ago
4 friends have a total of 3 same sized cookies. They want to divide them equally between the four of them. How much cookies does
Harlamova29_29 [7]
0.75 percent of a cookie
6 0
3 years ago
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