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Colt1911 [192]
3 years ago
7

[8 3 2]

Mathematics
2 answers:
Artyom0805 [142]3 years ago
6 0
The first dimension is the number of rows<span> in the matrix.

</span>There is 1<span> row.
</span>
The second dimension is the number of columns<span> in the matrix.
</span>
There are 3<span> columns.
</span>
<span>In conclusion, the dimensions of the matrix are 1 * 3. </span>
torisob [31]3 years ago
3 0
The matrix's dimensions are 1 by 3.
There is one row by three columns.

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HELP GIVING BRAINLYEST
natali 33 [55]

Answer:

58

Step-by-step explanation:

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3 years ago
PLZ HELP ASAP NEED HELP
SashulF [63]

Answer: x_1=2\\\\x_2=-\frac{1}{2}

Step-by-step explanation:

To find the zeros of the quadratic equation given in the exercise, you need to apply the proccedure shown below:

- You must rewrite it as following:

6x^2-9x-6=0

-You can apply the Quadratic formula, which is shown below:

x=\frac{-b\±\sqrt{b^2-4c}}{2a}

In this case:

a=6\\b=-9\\c=-6

- Therefore, when you substitute values, you obtain:

x=\frac{-(-9)\±\sqrt{(-9)^2-4(6)(-6)}}{2(6)}

x_1=2\\\\x_2=-\frac{1}{2}

4 0
3 years ago
Kelsey gave the cashier $30 to pay for 4 pounds of steak. The cashier gave her $3.12 in change. Each pound of steak cost the sam
vagabundo [1.1K]

Answer:

B

Step-by-step explanation:

30-3.12=26.88 divide that by 4 and you get 6.72

5 0
3 years ago
Read 2 more answers
What number should be added to both sides of the equation to complete the square?<br> x2 - 6x = 5
ikadub [295]

Answer:

First of all, it is better to note that x2 is not equal to x² .In mathematics x2 is equal to 2nd x or 2x i.e. 2 times x=2*x=x*2.

I don't know what this question means ! But if it means to just confine x2 and -6x in a square or to make them part of a square then it could be done as follows.

Assume x2 as x² as per your needs as case may be.

Now use the identity

(a² - 2a×b + b²) =(a - b )²

Here , in LHS

a appears twice as in a² and in 2a×b.

So for given expression (x2 – 6x = 5) or (x² – 6x = 5) or (x² - 6x -5 =0)

Assume x=a

Then,

6x =2*x*3 =2*a*b

=> 3 = b

Thus

(x² - 6x -5 =0)

=> x² - 2*x*3 + 3² -3² -5 =0

=> ( x² - 2*x*3 + 3² ) - 3² -5 =0

=> (x - 3)² - 3² = 5

=> (x - 3)² = 5 + 3²

=> (x - 3)² = 5 + 9 = 14 = ( ±√(14) )²

Now comparing

(x² – 6x = 5) and (x - 3)² = 5 + 9,

it can be said that number 9 should be added to both sides of (x² – 6x = 5) or (x² – 6x) = ( 5 ) to make ( x² ) and (-6x ) as the constituting parts of the square (x-3)² .

I hope it helps.

Thank you  for patiently reading it.

6 0
3 years ago
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF
vladimir2022 [97]

Answer:

30°

Step-by-step explanation:

Law of Sines = \frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

\frac{2}{Sin 30} = \frac{2}{Sin B}

\frac{2}{Sin 30} = \frac{2}{Sin 30}

Therefore, m∠B = 30°

Hope that's right and helps

6 0
3 years ago
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