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alukav5142 [94]
3 years ago
14

PLZ HELP ASAP NEED HELP

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer: x_1=2\\\\x_2=-\frac{1}{2}

Step-by-step explanation:

To find the zeros of the quadratic equation given in the exercise, you need to apply the proccedure shown below:

- You must rewrite it as following:

6x^2-9x-6=0

-You can apply the Quadratic formula, which is shown below:

x=\frac{-b\±\sqrt{b^2-4c}}{2a}

In this case:

a=6\\b=-9\\c=-6

- Therefore, when you substitute values, you obtain:

x=\frac{-(-9)\±\sqrt{(-9)^2-4(6)(-6)}}{2(6)}

x_1=2\\\\x_2=-\frac{1}{2}

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Nat2105 [25]

<em><u>Question:</u></em>

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?

<em><u>Answer:</u></em>

The actual length of Hector room is 14 foot

<em><u>Solution:</u></em>

Given that, On the floor plan, his bedroom is 3 inches wide and 3\frac{1}{2} inches long

<em><u>The scale of floor plan is given as:</u></em>

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Therefore,

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From given question,

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I am joyous to assist you anytime.

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