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3 years ago

PLZ HELP ASAP NEED HELP

Mathematics

1 answer:

SashulF [63]3 years ago

4 0

Answer: $x_1=2\\\\x_2=-\frac{1}{2}$

Step-by-step explanation:

To find the zeros of the quadratic equation given in the exercise, you need to apply the proccedure shown below:

- You must rewrite it as following:

$6x^2-9x-6=0$

-You can apply the Quadratic formula, which is shown below:

$x=\frac{-b\±\sqrt{b^2-4c}}{2a}$

In this case:

$a=6\\b=-9\\c=-6$

- Therefore, when you substitute values, you obtain:

$x=\frac{-(-9)\±\sqrt{(-9)^2-4(6)(-6)}}{2(6)}$

$x_1=2\\\\x_2=-\frac{1}{2}$

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