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3 years ago

5

What is the length of the transverse axis? (x-2)^2/36 - (y+1)^2/64=1

2 answers:

Vesna [10]3 years ago

8 0

To solve this problem you must apply the proccedure shown below:

1. You have the following standard form for the hyperbola given in the problem above: <span> (x-2)^2/36 - (y+1)^2/64=1
</span> 2. Therefore, you can calculate the lengtn of the transverse axis as following:
Length of transverse axis=2a
a^2=36
a=√36
a=6
Length of transverse axis=2(6)=12
Then, the answer is:12

Oliga [24]3 years ago

4 0

Answer:

if anyone is looking for the conjugate axis its 16 :)

Step-by-step explanation:

apex

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Masteriza [31]

Hello Again! :)

This time I got the correct answer, for you this time....

$Jace$ $is$ $here$ $to$ $hel$ $^{p}$ :

⋆┈┈｡ﾟ❃ུ۪ ❀ུ۪ ❁ུ۪ ❃ུ۪ ❀ུ۪ ﾟ｡┈┈⋆

$The$ $answer$ $to$ $this$ $is$ :

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⋆ Proof, is shown below of the question:

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And Tell me if the answer is wrong. . .

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2 years ago

In a standard deck of playing cards, one-fourth of the cards are hearts.

makkiz [27]

Answer:

$\sf D) \quad \dfrac{1}{64}$

Step-by-step explanation:

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

Probability of drawing a heart from one deck:

$\sf \implies P(heart)=\dfrac{1}{4}$

Therefore, probability of drawing a heart from each of 3 decks:

$\sf \implies P(heart)\:and\:P(heart)\:and\:P(heart)=\dfrac{1}{4} \times \dfrac{1}{4} \times \dfrac{1}{4}=\dfrac{1}{64}$

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2 years ago

Question 3 of 33

Zinaida [17]

Answer:

B. Regular tessellation

6 0

2 years ago

Read 2 more answers

Can u guys help plz

solong [7]

I think the answers are Number 1 -2. Number 2. is 2. Number 3. is 4. Number. 4 is 6. And number 5. is 12. I hope this helps :)

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2 years ago

D = rt, for r<br><br><br><br> Someone please help me out?

lianna [129]

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

All you have to do is divide the t on both sides and you'll get...

$r=\frac{d}{t}$

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2 years ago