The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
Answer:
1199
Step-by-step explanation:
There are 22 terms in the sum:
23 + 26 + 29 + ... + 80 + 83 + 86 =
= (23 + 86) + (26 + 83) + ... + (53 + 56)
= 109 + 109 + ... + 109
= 11(109)
= 1199
Answer:
r≈5.36656314
Step-by-step explanation:
Since A=πr(r+) so we get that 226.08/pi≈72 or 226.08/3.14=72 we then plug it in to get 72=r(r+) so we get r≈5.36656314
Answer:
g(1) = 0
There is a remainder of 10 so you can automatically cross out 3 and 4.