Simplify pls help!!!

The probability of winning on an arcade game is 0. 659. if you play the arcade game 30 times, what is the probability of winning

mrs_skeptik [129]

The probability of winning exactly 21 times is:-0.32

Given,

The probability of winning on an arcade game, p = 0.659

Number of times you play arcade game, n = 30

By assuming this as a normal distribution, we get

Mean=μ=30×0.659 =19.77

Standard deviation, σ = $\sqrt{np(1-p)}$

= $\sqrt{30(0.659)(1-0.659)}$

≈ 2.60

Let X be a binomial variable

Then, the z score for x = 21 will be:

z = (x - μ) / σ = $\frac{21-19.77}{2.60}$

≈ 0.47

Now, the probability of winning exactly 21 times

P (x ≥ z) = P (21 ≥ 0.47) = 0.32

Hence the probability of winning exactly 21 times is 0.32

Learn more about probability here:-brainly.com/question/13067945

#SPJ4

5 0

2 years ago

Need help with the question in the attachment!

IceJOKER [234]

Answer:

The answer is 8.

Step-by-step explanation:

I used the calculator...

I just typed these equations on the calculator because its hard to do it in your head.

log 5root5 125 = 2 x=2

log 2root2 64 = 4 y= 4

The question wants the product of x and y which translates to x times y. x*y

SO.... 2*4 = 8

4 0

3 years ago

Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas

Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as $\sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} } ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\$

Using these result in equation a we get

f(x) = $\sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)$

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = $f '(x)=\sqrt{2} \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0$

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2 => x<π/4 => x∈[0,π/4]

2) π/4 + x > 3π/2 => x > 5π/4 => x∈[5π/4,2π]

from conditions 1 and 2 we have x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0

3 years ago

2b-3(1+b)=-3(b+7) whats the answer? and how do you do it??

ycow [4]

Answer:

B=-9

Step-by-step explanation:

Technically, I didn't solve it. I used an algebra calculator online called m a t h w a y. It helps a lot but if you really need to know how to solve it on pencil and paper I cannot help you.

I had to space out the website so it let me submit this answer btw

7 0

3 years ago

Read 2 more answers

In abc the measure of side c is 3.9cm if def has a dilation of abc with a scale factor of 2.5

photoshop1234 [79]

Complete Question:

In ABC, the measure of sides c is 3.9 cm If DEF is a dilation ABC with a scale factor of 2.5 what is the measure of side f

Answer:

f = 9.75

Step-by-step Explanation:

From the information given, a sketch of ∆ABC and ∆DEF with their corresponding sides and angles have been attached below.

∆DEF is a dilation of ∆ABC, which is said to be on a scale factor of 2.5.

The scale factor is a whole number, this implies that ∆DEF is an enlargement of ∆ABC.

Since side c = 3.9 cm, in ∆ABC corresponds to side f, in ∆DEF, therefore, the measure of f would be:

f = measure of c × scale factor

f = 3.9 cm × 2.5

f = 9.75

5 0

3 years ago