Answer:
Japan : 
California : 
Step-by-step explanation:
The magnitude of an earthquake on the Richter scale can be defined by

where E is the energy of the quake in joules.
Add 3.2 on both sides.

Multiply both sides by 3/2.


![[\because \log x=a\Rightarrow x=10^a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%3Da%5CRightarrow%20x%3D10%5Ea%5D)
.... (1)
It is given that the 2011 Tohoku earthquake in Japan measured 9.1 on the Richter scale.
Substitute M=9.1 in equation (1).

Therefore, the energy released by earthquake in japan is
.
It is given that the 1999 Hector Mine earthquake in eastern California had a magnitude of 7.1.
Substitute M=7.1 in equation (1).

Therefore, the energy released by earthquake in California is
.
<u><em>Answer:</em></u>
(c) 4.1 km
<u><em>Explanation:</em></u>
We are given that the height of the balloon is 4 km and that it is 1 km away from the station.
Setting up the diagram that describes the given scenario, we would end up with a right-angled triangle as the one shown in the attached image
<u>where:</u>
height of the balloon = 4 km represents one side of the triangle
distance between the base of the balloon and the station = 1 km represents the other side
distance between the balloon and the station is the length we want to find and it represents the hypotenuse of the triangle.
<u>To get the length of the hypotenuse, we will use the Pythagorean theorem</u>

<u>Substitute with the givens:</u>
= √17 ≈ 4.1 km
Hope this helps :)
Answer:
1/2
Step-by-step explanation:
Answer:
-1.28 AND 2.61
Step-by-step explanation:

use quadratic formula
x =
x = 
Solution/X-Intercepts: -1.28 AND 2.61
For angle one do 180-74 then divide by two and it will give you the angle for angle one and for angle two you just add the angle given and angle one then subtract by 180