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kotykmax [81]
3 years ago
13

How to write half of a as an expression ​

Mathematics
2 answers:
Flura [38]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

mario62 [17]3 years ago
6 0

Answer:

a/2 or 1/2*a

Step-by-step explanation:

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Y = 2x + 3 find f(0)
vichka [17]

If y=2x+1 then that means f(x)=2x+3 and when you plug in x=0 you get f(0)=2\cdot0+3=\boxed{3}.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME !!!!​
Natalka [10]

Answer:

B

Step-by-step explanation:

There are no repeating values for x, for different values plugged in for y.

3 0
3 years ago
Solve for y: 7x+8y s 14-16
romanna [79]

Answer:

y≤ -1/4 - 7x/8

Step-by-step explanation:

7 0
3 years ago
From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
Debra has ridden 57 miles of a bike course the course is 60 miles long what percentage of the course has Debra ridden so far
Reptile [31]

Hello!

To find our answer, we just divide.

57/60=0.95

We multiply by 100 to find our percent

100(0.95)-95

Therefore, our answer is 95%

I hope this helps!

4 0
3 years ago
Read 2 more answers
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